Answer:
9x+4
Step-by-step explanation:
remove the parentheses
Answer:
Answer is D
Step-by-step explanation:
(3,-7) and (1,-10) belong toD Variant
The number of tests that it would take for the probability of committing at least one type I error to be at least 0.7 is 118 .
In the question ,
it is given that ,
the probability of committing at least , type I error is = 0.7
we have to find the number of tests ,
let the number of test be n ,
the above mentioned situation can be written as
1 - P(no type I error is committed) ≥ P(at least type I error is committed)
which is written as ,
1 - (1 - 0.01)ⁿ ≥ 0.7
-(0.99)ⁿ ≥ 0.7 - 1
(0.99)ⁿ ≤ 0.3
On further simplification ,
we get ,
n ≈ 118 .
Therefore , the number of tests are 118 .
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Answer:
1 solution, 0
Step-by-step explanation:
In algebra, a variable can be equal to any amount of numbers depending on how it is used. In this case, m is only equal to the one value of 8, and therefore only has <u>one solution.</u>
m - 8
(8) - 8
0
Hi there! The answer is n = 10.
As you see at the powers of x, we need to add the exponents of the power we when multiply them.
The powers of y work the same way.
Hence, n = 10, since
