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Alex_Xolod [135]
2 years ago
14

PLEASE HELP ME IM NOT GOOD WITH GRAPHS​

Mathematics
1 answer:
Yuri [45]2 years ago
3 0

Answer:

b

Step-by-step explanation:

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An airplane travels about 1,500 Km in a straight line between Toronto and Winnipeg. However, the plane must climb to 10,000 m du
Anna007 [38]

Answer:416

Step-by-step explanation: Based on the given problem above, it requires a trigonometric solution. So here it goes:

The climb distance is:200 * Sec [ArcTan [10/200]] = 10√ 401 km

and the decent distance is:300 * Sec [ArcTan [10/300]] = 10√901 km

So add the given results above with 500 km and this will be the additional distance that plane moves through the air.

The answer would be in the unit meters.

((10√401 +10√901−500)∗1000)=416 meters

Hope this is the answer that you are looking for.

7 0
3 years ago
a large pizza is advertised to have 14 inch diameter. If a costumer orders two large pizzas, how many squares inches of pizza wi
kari74 [83]
Radius ^2 * pi = 1 pizza * 2 = area of 2 pizzas = 307.876 in ^2
5 0
3 years ago
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Brenda has $500 in her bank account. Every week she withdraws $30 for
JulsSmile [24]

Answer:

10 weeks

Step-by-step explanation:

lets build a equation for this

500-30(x)........where x is the number of weeks

500-30(10)= $200 left

so she can maximum withdraw money for about 10 weeks

5 0
2 years ago
Does the point (-4, 2) lie inside or outside or on the circle x^2 + y^2 = 25?​
stiv31 [10]

Given equation of the Circle is ,

\sf\implies x^2 + y^2 = 25

And we need to tell that whether the point (-4,2) lies inside or outside the circle. On converting the equation into Standard form and determinimg the centre of the circle as ,

\sf\implies (x-0)^2 +( y-0)^2 = 5 ^2

Here we can say that ,

• <u>Radius</u> = 5 units

• <u>Centre </u> = (0,0)

<u>Finding</u><u> </u><u>distance</u><u> between</u><u> </u><u>the </u><u>two </u><u>points</u><u> </u><u>:</u><u>-</u><u> </u>

\sf\implies Distance = \sqrt{ (0+4)^2+(2-0)^2} \\\\\sf\implies Distance = \sqrt{ 16 + 4 } \\\\\sf\implies Distance =\sqrt{20}\\\\\sf\implies\red{ Distance = 4.47 }

  • Here we can see that the distance of point from centre is less than the radius.

<u>Hence </u><u>the</u><u> </u><u>point</u><u> </u><u>lies </u><u>within</u><u> </u><u>the </u><u>circle</u><u> </u><u>.</u>

5 0
3 years ago
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Draw a pic of 3 and 5/6
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Answer is attached below.

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