<u>Vertex</u>
y = -(x + 3)² + 1
y = -(x + 3)(x + 3) + 1
y = -(x² + 3x + 3x + 9) + 1
y = -(x² + 6x + 9) + 1
y = -x² - 6x - 9 + 1
y = -x² - 6x - 8
-x² - 6x - 8 = 0
x = <u>-(-6) +/- √((-6)² - 4(-1)(-8))</u>
2(-1)
x = <u>6 +/- √(36 - 32)</u>
-2
x = <u>6 +/- √(4)
</u> -2<u>
</u>x = <u>6 +/- 2
</u> -2
x = <u>6 + 2</u> x = <u>6 - 2</u>
-2 -2
x = <u>8</u> x = <u>4</u>
-2 -2
x = -4 x = -2
y = -x² - 6x - 8
y = -(-4)² - 6(-4) - 8
y = -(16) + 24 - 8
y = -16 + 24 - 8
y = 8 - 8
y = 0
(x, y) = (-4, 0)
or
y = -x² - 6x - 8
y = -(-2)² - 6(-2) - 8
y = -(4) + 12 - 8
y = -4 + 12 - 8
y = 8 - 8
y = 0
(x, y) = (-2, 0)
<u>Axis of Symmetry</u>
The axis of symmetry is equal to -3.
<u />
Answer:
8- 3x
Step-by-step explanation:
1- Calculate
Correct!
When thinking of what determines a plane we can make the following comparison.
If a plane was the top part of a table, 3 legs, whose tops are points W, X and Y may hold it, as shown in the first picture.
but if the legs are in a line, as in the second figure, they may not hold the top part, so 3 collinear points cannot determine a plane.
Answer:
596.34m approx
Step-by-step explanation:
Given data
Let the Starting point be x
A helicopter flew north 325 meters from x
Then flew east 500 meters
Let us apply the Pythagoras theorem to solve for the resultant which is the distance from the starting position
x^2= 325^2+500^2
x^2=105625+250000
x^2= 355625
x= √355625
x=596.34m
Hence the distance from the starting point is 596.34m approx
Answer: 4:5
Step-by-step explanation:
