All categories

3 years ago

Please help me out on this please

Mathematics

1 answer:

Alina [70]3 years ago

7 0

Answer:

8/15

please like my answer and brainliest me HSHSSHSHS

You might be interested in

Which algebraic expression is equivalent to the expression below

djyliett [7]

21x + 84 + 12x - 16
33x + 68

The correct answer is 1.) 33x + 68.
Hope this helps!

4 0

3 years ago

Read 2 more answers

Help please ! It’s geometry

bearhunter [10]

Answer:

90 °

Step-by-step explanation:

$\sqrt{5 \times 12}$

$\sqrt[5]{3}$

$\sqrt{6 \times 5}$

$\sqrt[5]{3}$

6 0

3 years ago

I'm so d*mb‍ i need help i got the answer but i need help with the formulas and showing my work to get the answer

bazaltina [42]

Answer:youre not dum :)

Step-by-step explanation: e

5 0

1 year ago

2 • -1^3 - 3 • -1^2 +7

sertanlavr [38]

Simplify 1^3 to 1

2 × -1 - 3 × -1^2 + 7

Simplify 1^2 to 1

2 × -1 - 3 × -1 + 7

Simplify 2 × -1 to -2

-2 - 3 × -1 + 7

Simplify 3 × -1 to -3

-2 - (-3) + 7

Simplify brackets

-2 + 3 + 7

Simplify

3 0

4 years ago

Please help me with #'s 5&6

Fynjy0 [20]

$5.\\(x+3)^2+7=-2\qquad|-7\\\\(x+3)^2=-9 < 0\\\\\text{NO REAL SOLUTION}\\\\(x+3)^2=-9\to x+3=\pm\sqrt{-9}\\\\x+3=-3i\ \vee\ x+3=3i\qquad|-3\\\\\boxed{x=-3-3i\ \vee\ x=-3+3i}$

$6.\\4(x-10)^2=25\qquad|:4\\\\(x-10)^2=\dfrac{25}{4}\to x-10=\pm\sqrt{\dfrac{25}{4}}\\\\x-10=-\dfrac{\sqrt{25}}{\sqrt4}\ \vee\ x-10=\dfrac{\sqrt{25}}{\sqrt4}\\\\x-10=-\dfrac{5}{2}\ \vee\ x-10=\dfrac{5}{2}\\\\x-10=-2.5\ \vee\ x-10=2.5\qquad|+10\\\\\boxed{x=7.5\ \vee\ x=12.5}$

7 0

4 years ago