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docker41 [41]
2 years ago
5

In addition to carcinoma of the prostate, elevated prostate-specific antigen (PSA) can occur due to:

Biology
1 answer:
V125BC [204]2 years ago
6 0

Answer: Your answer would be C: benign prostatic hyperplasia

Explanation: In addition to prostate cancer, several benign (not cancerous) conditions can cause a person's PSA level to rise, particularly prostatitis (inflammation of the prostate) and benign prostatic hyperplasia (BPH) (enlargement of the prostate)

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Can you explain the function of teratogen such as thalidomide and alcohol in terms of environment factors that play a role in or
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Umm that really is a lot of words there but I will try to find a explanatory answer
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3 years ago
g protein-activated inwardly rectifying potassium channels mediate depotentiation of long-term potentiation
Svetlanka [38]

Long-term potentiation (LTP) is considered a cellular correlate of learning and memory. The presence of G protein-activated inwardly rectifying K(+) (GIRK) channels near excitatory synapses on dendritic spines suggests their possible involvement in synaptic plasticity. However, whether activity-dependent regulation of  channels affects excitatory synaptic plasticity is unknown. In a companion article we have reported activity-dependent regulation of GIRK channel density in cultured hippocampal neurons that requires activity oF receptors (NMDAR) and protein phosphatase-1 (PP1) and takes place within 15 min. In this study, we performed whole-cell recordings of cultured hippocampal neurons and found that NMDAR activation increases basal GIRK current and GIRK channel activation mediated by adenosine A(1) receptors, but not GABA(B) receptors. Given the similar involvement of NMDARs, adenosine  receptors, and PP1 in depotentiation of LTP caused by low-frequency stimulation that immediately follows LTP-inducing high-frequency stimulation, we wondered whether NMDAR-induced increase in GIRK channel surface density and current may contribute to the molecular mechanisms underlying this specific depotentiation. Remarkably, GIRK2 null mutation or GIRK channel blockade abolishes depotentiation of LTP, demonstrating that GIRK channels are critical for depotentiation, one form of excitatory synaptic plasticity.

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8 0
2 years ago
If the body temperature of a person is recorded as 37 degrees Celsius, what is the persons body temperature in k? Round your ans
maw [93]

Answer:

The right answer to this question is: 310k

Explanation:

There's a very good formula that can help us to find this answer, but first, we need to know the temperature scale  in Celsius and Kelvin, there's an image below that will help us gather information.

The formula is quite simple, check it below:

C/5  = K-273/5

putting the values we already have in the formula it would be like this:

37/5 = K-273/5

Cutting out the fives, we can have the final result

37= K-273

37+273 = K

K= 310.

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I think it’s A or C....
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