((6*2)+y)+(x+15)
i hope this helps if not sorry
Your grammar is wrong. You aren't asking a question. I don't want to be mean but yeah you need to ask a real question.
Opposite/adjacent= cosine
cos B= opp/adj
cosB= 7/12
B=cos^-1 (7/12)
(Type it into a graphing calculator)
B=54.3 degrees
Make sure your calculator is in degree mode and you use the inverse cosine.
By definition, the slope of a curve is the rate of change of the independent and dependent variables. When graphed in a Cartesian plane, the slope between any two point on the curve is equal to Δy/Δx. However, we should not that only a linear function has a constant slope. For this problem, the equation is quadratic. Hence, you must specify the point where we should get the slope.
In calculus, the slope is the first derivative of the equation:
<span>y=3x</span>²<span>-8
dy/dx = slope = 6x - 0
Thus, the slope at any point of the curve is 6x. For instance, you want to find the slope of the curve at point (1,1), then the slope is equal to 6(1) = 6 units.</span>
Since this is in point-slope form, you know one of the points, which is (1,7), and you know the slope, which is -3. So you can plot (1,7) on the graph and then use the slope to plot more points by going down 3 and right 1, or up 3 and left 1.
