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julia-pushkina [17]
3 years ago
6

Which expression is equivalent to 2(h+4)+6(g+3)+5h

Mathematics
1 answer:
Anton [14]3 years ago
6 0

The distributive property: <em>a(b + c) = ab + ac</em>

2(h + 4) + 6(g + 3) + 5h

= (2)(h) + (2)(4) + (6)(g) + (6)(3) + 5h

= 2h + 8 + 6g + 18 + 5h       <em>cimbine like terms</em>

= (2h + 5h) + 6g + (8 + 18)

<h3>= 7h + 6g + 26</h3>
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Sandra wants to use multiplication to solve 1/4 divided by 6=t
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Answer; 1/4 × 1/6

Step-by-step explanation:  To turn a fraction division sentence into a multiplication sentence, simply multiply the second fraction by its reciprocal. For example 1/4 ÷ 6/1 is equaled to 1/4 × 1/6.

I hope this helps! please vote brainliest if so

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What is the factored form of the function f(x)=x^3+8x^2+5x−50?
Inga [223]

Answer:

the factors of  f(x)=x^3+8x^2+5x-50 are (x-2)(x+5)(x+5)

Step-by-step explanation:

We need to factorise the function f(x)=x^3+8x^2+5x-50

If a number is a factor of this function than it must be completely divisible by last co-efficient. Our last co-efficient is -50

Checking few numbers:

f(1)=(1)^{3}+8(1)^2+5(1)-50\\f(1)=1+8+5-50\\f(1)=-32\\Now \ putting \ x= 2 \\f(2)=(2)^{3}+8(2)^2+5(2)-50\\f(2)=8+8(4)+10-50\\f(2)=8+32+10-50\\f(2)=0

So, f(2)=0 which means x-2 is a factor of the given function. Now we will perform long division of x^3+8x^2+5x-50 by (x-2) to find other factors

The long division is shown in figure attached.

After long division we get: x^2+10x+25

The equation x^2+10x+25 can be further simplified as: (x+5)(x+5) or (x+5)^2

So, the factors of  f(x)=x^3+8x^2+5x-50 are (x-2)(x+5)(x+5)

3 0
3 years ago
A woman 38 years old has a daughter 14 years old. How many years ago was the woman 8 times older than the daughter?
Kisachek [45]
6 yrs ago was when she was 8 times older
3 0
4 years ago
The path of a projectile launched from a 20-ft-tall tower is modeled by the equation y = -5x2 + 40x + 20. What is the maximum he
Otrada [13]

Answer:

30.49 m

Step-by-step explanation:

To obtain the maximum height, we solve for the value x when dy/dx = 0.

Since, y = -5x² + 40x + 20

dy/dx = d[-5x² + 40x + 20]/dx

dy/dx = -10x + 40

Since dy/dx = 0,

-10x + 40 = 0

-10x = -40

x = -40/-10

x = 4

Substituting x = 4 into the equation for y, we have

y = -5x² + 40x + 20

y = -5(4)² + 40(4) + 20

y = -5(16) + 160 + 20

y = -80 + 160 + 20

y = 80 + 20

y = 100 ft

Since y is in feet, we convert to meters.

Since 1 m = 3.28 ft, 100 ft = 100 ft × 1 m/3.28 ft = 30.49 m

So, the maximum height, in meters  reached by the projectile is 30.49 m

3 0
3 years ago
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