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2 years ago

15. Desde la punta de un edificio el hombre araña lanza una tela a 500 metros, de la base del edificio

Mathematics

1 answer:

Umnica [9.8K]2 years ago

8 0

Step-by-step explanation:

the correct answer will be 93

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HELP ASAP PLEASE!! The Great Pyramid of Cheops is the largest pyramid in the world. It was built around 2500 B.C. by Khufu, or C

OlgaM077 [116]

Answer:

138, 460 m²

Step-by-step explanation:

How To Find Volume of Pyramid With Slant Height? If 'x' is the base length, 's' is the slant height, and 'h' is the height of a regular pyramid, then they satisfy the equation (the Pythagoras theorem) (x/2)2 + h2 = s2.

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3 years ago

The population of a once very popular city of 250,000 people has been decreasing by 3.5% each year. Write an exponential decay f

vladimir2022 [97]

Y= 250000-8750t

3.5 percent of 250000 is 8750, if that’s the amount decreasing each (t) years, you multiply that number by number of years taken into account.

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3 years ago

What is the equation of the

kati45 [8]

Answer:

y = $\frac{1}{3}$ x + 4

Step-by-step explanation:

the equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

y = - 3x + 6 ← is in slope- intercept form

with slope m = - 3

given a line with slope m then the slope of a line perpendicular to it is

$m_{perpendicular}$ = - $\frac{1}{m}$ = - $\frac{1}{-3}$ = $\frac{1}{3}$ , then

y = $\frac{1}{3}$ x + c ← is the partial equation of the perpendicular line

to find c substitute (3, 5 ) into the partial equation

5 = 1 + c ⇒ c = 5 - 1 = 4

y = $\frac{1}{3}$ x + 4 ← equation of perpendicular line

6 0

2 years ago

A NASA test rocket launch is set up so that once the rocket takes off from a landing platform,It will splash down safely in a bo

Aleonysh [2.5K]

Answer:

237.87 m/s

Step-by-step explanation:

This is a projectile question.

We use the equation for the range of a projectile since we are given the horizontal distance and angle of projection.

So, R = U²sin2θ/g where R = range, U = initial speed of rocket, θ = projection angle and g = acceleration due to gravity = 9.8 m/s².

Since it is given that the water body is 5 km away, R = 5 km = 5000 m and θ = 30°

So, making U subject of the formula, we have that

U = √(gR/sin2θ)

So, substituting the values of the variables, we have

U = √[9.8 m/s² × 5000 m/sin(2 × 30°)]

U = √[49000 m²/s²/sin60°]

U = √[49000 m²/s²/0.8660]

U = √[56,580.33 m²/s²]

U = 237.87 m/s

So the minimum speed of the rocket necessary to make sure the rocket reaches the water surface is U = 237.87 m/s

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3 years ago

Howwww??????<br> Answer???

Anika [276]

8x - 12 = 6x + 2

8x - 12 + 12 = 6x + 2 + 12

8x = 6x + 14

8x - 6x = 6x + 14 - 6x

2x = 14

2x/2 = 14/2

X = 7

8 0

3 years ago

Read 2 more answers