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erastova [34]
1 year ago
14

Show how to simplify y-8 = 3/4x [x-(-6)]

Mathematics
1 answer:
notsponge [240]1 year ago
7 0

To simplify the equation, we have y = \frac{3}{4x^2 + 24x} + 8

<h3>How to simply the expression</h3>

Given the expression

y-8 = 3/4x [x-(-6)]

First, expand the bracket

y - 8= \frac{3}{4x^2 + 24x}

Make 'y' the subject of formula

y = \frac{3}{4x^2 + 24x} + 8

Thus, to simplify the equation, we have y = \frac{3}{4x^2 + 24x} + 8

Learn more about algebraic expression here:

brainly.com/question/4344214

#SPJ1

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√50, √8, whats the area of the triangle no picture
Bas_tet [7]

Answer:

Area  = 10

Step-by-step explanation:

(\sqrt{50}×\sqrt{8})  ÷ 2 = 10

6 0
2 years ago
X = -1+y
gtnhenbr [62]

Answer:

y = 2

Step-by-step explanation:

x= -1+y

2x-y=0

2(-1+y)-y=0

-2+2y-y=0

-2+y=0

-2+2+y=0+2

y=2

hope it's helpful ❤❤❤❤

THANK YOU.

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6 0
2 years ago
Read 2 more answers
A school P is 16km due west of a school Q. what is the bearing of Q from P​
Irina-Kira [14]

Answer:

16Km due east of school P

Step-by-step explanation:

Given

A school P is 16km due west of a school Q

Thus, we can say that distance PQ = 16 km.

________________________________

now we have to find  the bearing of Q from P​

As distance is same

distance PQ = distance QP

Thus,

Distance will remain same of 16 km.

For direction,

If Q is west of P, then P will be east of QP------------------>Q

as shown in figure P is west of Q,

now from point P , Q is west P.

Thus,

Bearing of  School Q from P is 16Km due east of school P

7 0
3 years ago
james was diving in the ocean. he decided to ascend 11 feet to be able to see the coral better. he was then at -13 feet from the
vesna_86 [32]

Answer: -1 because - 13 - 11 will = -1

5 0
2 years ago
An expression is shown.
Anettt [7]

Answer:

im pretty sure its D :) hope this helps you out.

7 0
2 years ago
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