we know that
The measure of the interior angle is the half-sum of the arcs comprising it and its opposite.
so
<u>Find the measure of the angle LAM</u>
m∠LAM is equal to
![\frac{1}{2}*[arc\ KJ+arc\ LM]= \frac{1}{2}*[170+80]\\\\=125\ degrees](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D%2A%5Barc%5C%20KJ%2Barc%5C%20LM%5D%3D%20%5Cfrac%7B1%7D%7B2%7D%2A%5B170%2B80%5D%5C%5C%5C%5C%3D125%5C%20degrees)
<u>Find the measure of the angle MAJ</u>
we know that
m∠LAM+m∠MAJ=
° ------> by supplementary angles
m∠MAJ=
m∠MAJ=
°
therefore
<u>the answer is</u>
The measure of the angle MAJ is 
The length and width that will maximize the area are 175 ft and 87.5 ft respectively
The largest area that can be enclosed is 15312.5 ft²
<h3>Area of a rectangle</h3>
where
l = length
w = width
The fencing is 350 ft it is use to enclose a rectangular plot with a river occupying one part.
Therefore,
perimeter = l + 2w
350 = l + 2w
l = 350 - 2w
area = (350 - 2w)w
(350 - 2w)w = 0
where
w = 0 or 175
average = 175/2 = 87.5
Hence, the max area is at w = 87.5 ft
Therefore,
l = 350 - 2(87.5) = 175 ft
length = 175 ft
width = 87.5 ft
Therefore,
area = 175 × 87.5 = 15312.5 ft²
Therefore, the largest area that can be enclosed is 15312.5 ft²
learn more on rectangle here: brainly.com/question/11630499
She can fill 24 glasses with 3 containers of tea
