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Oliga [24]
2 years ago
15

Write out the form of the partial fraction decomposition of the function. Do not determine the numerical values of the coefficie

nts.\frac{t^4+t^2+1}{(t^2+4)(t^2+2)^2}
Mathematics
1 answer:
maria [59]2 years ago
3 0

The form of the partial fraction decomposition is \frac{At + B}{(t^2 + 4)} + \frac{Ct + D}{(t^2 + 2)} + \frac{Et + F}{(t^2 + 2)^2}

<h3>How to decompose the function?</h3>

The fraction is given as:

\frac{t^4 + t^2 + 1}{(t^2 + 4)(t^2 + 2)^2}

To decompose the above, we make use of the following rule:

\frac{px^n + qx^m +....+ r}{(x^2 + a)(x^2 + b)^2} = \frac{Ax + B}{(x^2 + a)} + \frac{Cx + D}{(x^2 + b)} + \frac{Ex + F}{(x^2 + b)^2}

So, we have:

\frac{t^4 + t^2 + 1}{(t^2 + 4)(t^2 + 2)^2} = \frac{At + B}{(t^2 + 4)} + \frac{Ct + D}{(t^2 + 2)} + \frac{Et + F}{(t^2 + 2)^2}

Hence, the form of the partial fraction decomposition is \frac{At + B}{(t^2 + 4)} + \frac{Ct + D}{(t^2 + 2)} + \frac{Et + F}{(t^2 + 2)^2}

Read more about partial fraction decomposition at:

brainly.com/question/2516522

#SPJ1

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Answer:

\boxed{\textsf{ The LCM of 56 , 42 , 28 is \textbf{ 168}.}}

Step-by-step explanation:

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Answer:

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Step-by-step explanation:

The given function is f(x) = (x + 2)⁴

The range of the minimum = 0 < x < 3

At a local minimum/maximum values, we have;

f'(x) = \dfrac{(-x + 2)^4}{dx}  = -4 \cdot (-x + 2)^3 = 0

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f''(x) = \dfrac{ -4 \cdot (-x + 2)^3}{dx}  = -12 \cdot (-x + 2)^2

When x = 2, f''(2) = -12×(-2 + 2)² = 0 which gives a local minimum at x = 2

We have, f(2) = (-2 + 2)⁴ = 0

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Given that the minimum of the function is at x = 2, and the function is (-x + 2)⁴, the absolute local maximum will be at the maximum value of (-x + 2) for 0 < x < 3

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Therefore, the maximum value of -x + 2, is at x = 0 and the maximum value of the function where 0 < x < 3, is (0 + 2)⁴ = 16

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