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AleksAgata [21]
2 years ago
12

A group of students at Brunel university took a test in marketing and they needed to score 50 to pass. The results showed that t

he final grades have a mean of 62 and a standard deviation of 8. Suppose we approximate the distribution of these grades by normal distribution. Based on this information, you are required to perform the following; a) what percetage(to 3 decimals) of the students scored more than 78? B) what percentage of the students to 3 decimal places scored under 50? And c) what percentage to 3 decimal places of the students scored between 60 and 80?
Mathematics
1 answer:
MrRa [10]2 years ago
7 0

Answer:

My answer: 15.87%

Step-by-step explanation:

The Final grades follows normal distribution.

It means =70

The Given standard deviation =10

The normal random variable of a standard normal distribution is called a standard score or a z-score. In Every normal condition, random variable X will be transformed into a z score via the following equation:

z=(X)

But when X is a normal random variable, μ is the mean of X.

For That, it is X=60

Z=(60−70)/10=−1

P(X<60)=P(Z<−1)

=0.1587

Hence percent of students failed in test is 15.87%

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Which scenario best matches the linear relationship expressed in the equation y=-14+1700
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Question:

Which scenario best matches the linear relationship expressed in the equation y = –14x + 1,700?

1) Kent has $1,700 in his bank account and spends $14 each week.

2) Kent has $1,700 in his bank account and deposits $14 each week.

3) Kent had $1,700 in his bank account and deposited another $14.

4) Kent has $14 in his bank account and spent $1,700.

Answer:

Option  1) Kent has $1,700 in his bank account and spends $14 each week.

Step-by-step explanation:

Let x denote the number of weeks.

Option 1: Kent has $1,700 in his bank account and -14x as the negative sign denotes how much amount he spend each week.

Thus, Option 1 is the correct answer.

Option 2: Kent has $1,700 in his bank account and deposits $14 each week.

Writing it as equation, we have, y=14x+1700 which is not the expressed linear equation.

Hence,  Option 2 is not the correct answer.

Option 3: Kent had $1,700 in his bank account and deposited another $14.

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Hence,  Option 3 is not the correct answer.

Option 4: Kent has $14 in his bank account and spent $1,700.

Writing it as equation, we have, y=14-1700 which is not the expressed linear equation.

Hence,  Option 4 is not the correct answer.

Thus, the scenario that matches the linear equation relationship expressed in the equation is Option 1.

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