Ask question

Ask question

All categories

3 years ago

8

HELP! What is AB? WILL GIVE BRAINLIEST!

1 answer:

Natalija [7]3 years ago

3 0

AB = BC

3x-4=5x-10
-4=2x-10
6=2x
3=x

AB = 3x-4
AB = 3 (3)-4
AB = 9-4
AB =5

Therefore, AB is 5.

BC = 5x-10
BC = 5(3)-10
BC = 15-10
BC= 5

You might be interested in

Which expression is equivalent to (3−2^2) 5 ? 5−3^2 5−2^2 2^2−5 3^2−5

tamaranim1 [39]

Well (3-2^2)5 = -5
and 5-3^2=-4
5-2^2=1
2^2-5=-1
3^2-5=4
but if you have to multiply them by 5 as well then (2^2-5)5=-5

8 0

3 years ago

What is this?<br><br> :) Help Plz!!!

Eduardwww [97]

Im 70% sure its blue x=1,x=-5/2

Hope i helped if did plz mark as brainliest^-^

3 0

3 years ago

Find number a and k so that x-2 is afactor<br>OF F(x)=x4-2ax tax-<br>X+k and F(-1)=3

Slav-nsk [51]

Question:

Find numbers a and k so that x-2 is a factor of

$f(x)=x^4-2ax^3+ax^2- x+k$

and

$f(-1)=3$

Answer:

$k = -2$ and $a=1$

Step-by-step explanation:

Given

$f(x)=x^4-2ax^3+ax^2- x+k$

$Factor:\ x - 4$

$f(-1)=3$

Required

Find a and k

For $f(-1)=3$

Substitute -1 for x

$f(x)=x^4-2ax^3+ax^2- x+k$

$f(-1) = (-1)^4 - 2a *(-1)^3 + a*(-1)^2 - (-1) + k$

$f(-1) = 1 - 2a *-1 + a*1 +1 + k$

$f(-1) = 1 +2a + a +1 + k$

$f(-1) = 2 +3a + k$

Substitute 3 for f(-1)

$3 = 2 +3a + k$

Collect Like Terms

$3 - 2 = 3a + k$

$1 = 3a + k$

Also:

If $x - 2$ is a factor, then

$f(2) = 0$

Substitute 2 for x and 0 for f(x)

$f(x)=x^4-2ax^3+ax^2- x+k$

$0 = 2^4 - 2a * 2^3 + a * 2^2 - 2 + k$

$0 = 16 - 2a * 8 + a * 4 - 2 + k$

$0 = 16 - 16a + 4a - 2 + k$

$0 = 16 - 12a - 2 + k$

Collect Like Terms

$2 - 16 = - 12a + k$

$-14 = k - 12a$

$k = 12a - 14$

Substitute 12a - 14 for k in $1 = 3a + k$

$1 = 3a + 12a - 14$

$1 = 15a - 14$

Collect Like Terms

$15a = 1 + 14$

$15a = 15$

Solve for a

$a = \frac{15}{15}$

$a=1$

Substitute 1 for a in $k = 12a - 14$

$k = 12 * 1 - 14$

$k = 12 - 14$

$k = -2$

3 0

2 years ago

Please help me understand

xeze [42]

Step-by-step explanation:

A=2(wl+hl+hw)=2x(14x7+7x7+7x14)=490

Option B is the correct answer

5 0

2 years ago

Find the median first quarrile, third quartile, interquartile range, and an outliers for each set of data

Igoryamba

The outlier is 68

The median is 102
First quartile: 87
Third Quartile: 115
The interquartile range is 87-115

3 0

3 years ago