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Dovator [93]
2 years ago
15

Which of the following are solutions to the equation below?

Mathematics
1 answer:
zhannawk [14.2K]2 years ago
6 0

Answer:

x = (√10  -3)/2  and (-√10  -3)/2

Step-by-step explanation:

(2x+3)^2 = 10

To solve the equation, take the square root of each side

sqrt((2x+3)^2) = ±√10

2x+3 = ±√10

Subtract 3 from each side

2x+3-3 = ±√10  -3

2x = ±√10  -3

Divide each side by 2

2x/2 = (±√10  -3)/2

x = (±√10  -3)/2

There are two solutions

x = (√10  -3)/2

and (-√10  -3)/2

       

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use the formula 1/2(base1+base)x height

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8 0
3 years ago
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F(x)=3x^2+6x-18 , find f(10)
lord [1]

Answer:

f(10)=342

Step-by-step explanation:

f(10)= 3(10)^2+6(10)-18

complete your exponet first and multiply 6(10)

f(10)=3(100)+60-18

multiply the 3(100)

f(10)=300+60-18

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5 0
3 years ago
The equation of circle having a diameter with endpoints (-3, 1) and (5, 7) is
nydimaria [60]
The equation of a circle:
(x-h)^2+(y-k)^2=r^2
(h,k) - the coordinates of the center
r - the radius

The center is the midpoint of the diameter.
(-3,1) \\
x_1=-3 \\ y_1=1 \\ \\
(5,7) \\
x_2=5 \\ y_2=7 \\ \\
\hbox{the midpoint: } (\frac{x_1+x_2}{2},\frac{y_1+y_2}{2}) \\
\frac{x_1+x_2}{2}=\frac{-3+5}{2}=\frac{2}{2}=1 \\
\frac{y_1_y_2}{2}=\frac{1+7}{2}=\frac{8}{2}=4 \\
\Downarrow \\
(1,4) \\ h=1 \\ k=4

The radius is half the diameter, or the distance from one of the endpoints to the center.
r=\sqrt{(x_1-h)^2+(y_1-k)^2}=\sqrt{(-3-1)^2+(1-4)^2}=\\
=\sqrt{(-4)^2+(-3)^2}=\sqrt{16+9}=\sqrt{25}=5 \\ \Downarrow \\
r^2=5^2=25

The equation of the circle:
\boxed{(x-1)^2+(y-4)^2=25}
8 0
3 years ago
Read 2 more answers
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