What is (1-2)???????????????
2 answers:
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Answer:
(A)The absolute maximum of f(x) is at x=5
Step-by-step explanation:
F(x)=−2x³+21x²−60x on [1,6]
Find the first derivative.
f'(x)=-6x²+42x-60
Set the first derivative equal to zero.
-6x²+42x-60=0
Solve to find the critical points.
x=2,5
Next, we use the endpoints and all critical points on the interval to test for any absolute extrema over the given interval.
x=1,2,5,6
This is done by evaluating the function at x=1,2,5,6.
F(1)=−2(1)³+21(1)²−60(1)=-41
F(2)=−2(2)³+21(2)²−60(2)=-52
F(5)=−2(5)³+21(5)²−60(5)=-25
F(6)=−2(6)³+21(6)²−60(6)=-36
The maximum will occur at the highest f(x) value and the minimum will occur at the lowest f(x) value.
Absolute Maximum: (5,-25)
Absolute Minimum: (2,-52)
The graph is attached.
The absolute minimum and maximum of f(x) are (2,-52) and (5,-25) respectively.
Answer:
- 615.8 m^2
- 314.2 cm^2
- 38.5 ft^2
- 113.1 in^2
- 1075.2 m^2 . . . . corrected to 107,521.0 m^2
- 490.9 yd^2
- 18.8 m
- 94.2 in
- 81.7 ft
- 59.7 km
- 131.9 cm
- 144.5 yd
Step-by-step explanation:
The formula for the area of a circle is ...
A = πr^2
For each of the given circles, use the value of the radius in this formula. For example, for problem 2, the diameter is shown as 20 cm, so the radius is half that, 10 cm. Putting that value into the formula gives ...
A = 3.14159·(10 cm)^2 = 314.159 cm^2 ≈ 314.2 cm^2
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The formula for the circumference of a circle is ...
C = 2πr . . . . when the radius is given
or ...
C = πd . . . . . when the diameter is given
As above, put the value for radius (or diameter) into the appropriate formula and evaluate it. For problem 12, that is ...
C = 3.14159·(46 yd) = 144.513 yd ≈ 144.5 yd
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<em>Comment on doing lots of problems</em>
The idea behind having you do lots of problems is that repetition will help you remember the formula and/or how to use it. Personally, I find it tedious, so I like to let a spreadsheet or graphing calculator do the arithmetic when there are lots of identical problems (just with different numbers). This question is posted in the college math forum, so we assume you have a graphing calculator and know how to use it.
The attached photo shows a calculator set up to do the calculation and the rounding for each of the problem types. To get the answer to the last area calculation requires scrolling to the right to find it is 490.9 yd^2.
Note that we have used the calculator's button for π. If you put the number in yourself, use the one shown above, or the ratio 355/113, which is accurate to 7 digits.
In some cases, the numbers in the photo are not terribly clear. I took my best guess. In the event I read the value or units incorrectly, you will have to make appropriate adjustments—that is, do the calculation yourself.
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Late edit: apparently I read the number wrong for problem 5. The area of a circle with radius 185 m is 107,521.0086 m^2, which rounds to 107,521.0 m^2. Oops.
