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kobusy [5.1K]
2 years ago
5

Which one of the following situations could be represented by a linear function?

Mathematics
1 answer:
Katena32 [7]2 years ago
4 0
The answer A for a linear function
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5 1/3 in decimal form​
STatiana [176]

Answer:

5.33

Step-by-step explanation:

5+1/3

=5.3333

=533.33333333%

7 0
4 years ago
Read 2 more answers
Can anyone help me?​
vlada-n [284]

Answer:

a. 3.5 b. 2.25 c. 47.8 deg

Step-by-step explanation:

7 0
3 years ago
Find all the zeros of the polynomial 2x4 - 9x3 + 5x2 + 3x -1, if two of its zeros are ( 2 +√ ) and (2 - √ ) .
elena-s [515]

Answer:

x=-\frac{1}{2} , 1, (2+\sqrt{3} ), (2-\sqrt{3} )

Hope this helps!

8 0
3 years ago
Solve this x²+8/10 -x = 10/2
AysviL [449]
x^2+\frac{8}{10}-x=\frac{10}{2}\\
x^2-x+\frac{8}{10}-\frac{10}{2}=0\\
x^2-x+\frac{8}{10}-\frac{50}{10}=0\\
x^2-x-\frac{42}{10}=0\\
x^2-x+\frac{1}{4}-\frac{1}{4}-\frac{42}{10}=0\\
(x-\frac{1}{2})^2=\frac{1}{4}+\frac{42}{10}\\
(x-\frac{1}{2})^2=\frac{5}{20}+\frac{84}{20}\\
(x-\frac{1}{2})^2=\frac{89}{20}\\
x-\frac{1}{2}=\sqrt{\frac{89}{20}} \vee x-\frac{1}{2}=-\sqrt{\frac{89}{20}}\\
x=\frac{1}{2}+\frac{\sqrt{89}}{\sqrt{20}} \vee x=\frac{1}{2}-\frac{\sqrt{89}}{\sqrt{20}}\\



x=\frac{1}{2}+\frac{\sqrt{89}}{2\sqrt{5}} \vee x=\frac{1}{2}-\frac{\sqrt{89}}{2\sqrt5}}\\
x=\frac{1}{2}+\frac{\sqrt{445}}{10} \vee x=\frac{1}{2}-\frac{\sqrt{445}}{10}}\\
x=\frac{5+\sqrt{445}}{10} \vee x=\frac{5-\sqrt{445}}{10}}\\
7 0
4 years ago
Graph the line whose y-intercept is -7 and whose x-intercept is 1
vesna_86 [32]

Answer:

y=7x -7

Step-by-step explanation:

We are given two points, the y - intercept and the x - intercept.

The y - intercept being: ( 0, -7 )

The x - intercept being: ( 1, 0 )

The equation of a line in slope - intercept form is:

y = mx + b, where m is the slope and b is the y - intercept.

We already have the y - intercept. So far we have:

y = mx - 7

What we're missing is the slope.

To find the slope, we can use this formula:

\frac{y_{2}-y_{1}  }{x_{2}-x_{1}}, where x_{2} and x_{1} are the x - coordinates of both points and y_{2} and x_{1} are the y - coordinates of both points.

m=\frac{0-(-7)}{1-0} \\\\m=\frac{7}{1}\\m=7

We now have the missing piece, the slope, so the equation now is:

y=7x -7

3 0
3 years ago
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