Question

\sqrt{27} - \sqrt{ 12} + \sqrt{48 }

Answer 1

Answer:

$5\sqrt{3}$

Step-by-step explanation:

I'm assuming you're asking for most simplified form?

Original Equation:

$\sqrt{27} - \sqrt{12} + \sqrt{48}$

Rewrite sqrt(27) using the exponent property: $\sqrt[n]{a} * \sqrt[n]{b} = \sqrt[n]{ab}$

$\sqrt{9} * \sqrt{3} -\sqrt{12} + \sqrt{48}$

Simplify sqrt(9)

$3\sqrt{3} -\sqrt{12} + \sqrt{48}$

Rewrite the radical sqrt(12)

$3\sqrt{3} -\sqrt{4}\sqrt{3} + \sqrt{48}$

Simplify sqrt(2)

$3 \sqrt{3} -2\sqrt{3} + \sqrt{48}$

Rewrite the radical sqrt(48)

$3\sqrt{3} -2\sqrt{3} + \sqrt{16}\sqrt{3}$

Simplify the sqrt(16)

$3\sqrt{3} -2\sqrt{3} + 4\sqrt{3}$

You can think of sqrt(3) as x, in which case you have 3x - 2x + 4x, so you just add the coefficients and leave the sqrt(3) alone.

Subtract 2 from 3

$1\sqrt{3} + 4\sqrt{3}$

Add 1 and 4

$5\sqrt{3}$