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2 years ago

HELP I REALLY NEED HELP

Mathematics

1 answer:

zepelin [54]2 years ago

6 0

Answer: 72 inches squared

Step-by-step explanation:

So, the real floor of a classroom is 36 feet by 32 feet.

And the scale drawing, has length of the classroom equal to 9 inches.

What is the area in square inches of the floor in the scale drawing

1 foot = 12 inches

The length of the classroom, measured in feet, has been multiplied by 12, to get converted in inches. After that, it has been divided by a number, a proportion, to get to 9 inches.

36feet * 12 / x = 9 inches

432 inches / x = 9 inches

Now, to solve for x, we can cross-multiply

432 inches = 9x inches

Divide 9 inches on both sides.

x = 48

To solve the exercise, we need to calculate the floor's area in the scale drawing.

We have the length = 9 inches.

Now, let's calculate the width

Width = 32 feet * 12 / 48

Width = 384 inches / 48

Width = 8 inches

Area = Length * Width

Area = 9 inches * 8 inches

Area = 72 inches squared

Hope I helped!

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3 years ago

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kupik [55]

We have to break each degree in terms of 90

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Which is in third quadrant, therefore cosine is negative hence

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C) $tan180^\circ=tan(90\times2+0)$

Which is in third quadrant, therefore tangent is positive hence

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D) $csc180^\circ=csc(90\times2+0)$

Which is in third quadrant, therefore cosec is negative hence

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E) $sec180^\circ=sec(90\times2+0)$

Which is in third quadrant, therefore secant is negative hence

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Hope this will help

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3 years ago

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slavikrds [6]

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3 years ago

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astraxan [27]

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