An applicable equation of a vertical parabola in vertex form is:
y-k = a(x-h)^2
Let x=2, y=4, h=-1 and k=-1, where (h,k) is the vertex. Then,
4-(-1) = a(2-[-1])^2, which becomes 5 = a(9). Therefore, a = 5/9, and the
equation of the parabola is
y+1 = (5/9)(x+1)
The linear combination method is the same as the elimination method. Let's multiply the second equation by -2 so the x terms cancel each other out. When we do that we get a system of
and
. The x-terms cancel each other out giving us
and y = -3. Now sub -3 into one of the equations to solve for x. x+2(-3)=-4, and x - 6 = -4. x = 2. So the solution for our system is (2, -3)
2.3495x10^4th. Count how many places you move the decimal, that is what power you apply to 10 after converting it to a decimal.
It could be seen from the table that when x is 2, the y value is 0. Thus, it can be concluded that the x intercept is (2,0)
The correct answer is B
<span>If the coordinates of a point are both negative, then the point is in Quadrant III.
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