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Gennadij [26K]
2 years ago
6

Please help ASAP Please help ASAP Please help ASAP

Mathematics
2 answers:
larisa [96]2 years ago
6 0

Answer:

9% only a guess.May not be correct..

murzikaleks [220]2 years ago
4 0

Answer:

Step-by-step explanation:

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Can someone ONE person tutor me in math?plsss
Rina8888 [55]

Answer:

I can

Step-by-step explanation:

I'm taking precalculus currently

5 0
2 years ago
Read 2 more answers
What is the answer to <br> 7/9 - 3/8=
antiseptic1488 [7]
7/9-3/8
56/72-27/72
29/72
5 0
3 years ago
Jeanne Crawford had $9,675.95 deposited in an account paying
Anni [7]

Answer:

a. $10,943.30

b. $1,267.35

Step-by-step explanation:

P = $9,675.95

r = 6.25% = 0.0625

t = Compounded Semiannually = 2

a. Amount after 2 Years

n = 2

A = P [1 + (r / n)]^nt

A = $9,675.95 [1 + (0.0625 / 2)]² ˣ ²

A = $9,675.95 [1 + 0.03125]⁴

A = $9,675.95 [1.03125]⁴

A = $9,675.95 x 1.130982

A = $10,943.30

b. Compound Interest

Compound Interest = Final Amount - Principal Amount

Compound Interest = $10,943.30 - $9,675.95

Compound Interest = $1,267.35

8 0
3 years ago
51 is 17% of which number?
jeyben [28]

Answer:

300

Step-by-step explanation:

17/100x=51

x=300

17/100(300)=51

7 0
3 years ago
Read 2 more answers
The Information Technology Department at a large university wishes to estimate the proportion of students living in the dormitor
nadya68 [22]

Answer:

n=\frac{0.5(1-0.5)}{(\frac{0.05}{1.96})^2}=384.16  

And rounded up we have that n=385

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

Solution to the problem

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 99% of confidence, our significance level would be given by \alpha=1-0.99=0.01 and \alpha/2 =0.005. And the critical value would be given by:

z_{\alpha/2}=-2.58, z_{1-\alpha/2}=2.58

The margin of error for the proportion interval is given by this formula:  

ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}    (a)  

And on this case we have that ME =\pm 0.05 and we are interested in order to find the value of n, if we solve n from equation (a) we got:  

n=\frac{\hat p (1-\hat p)}{(\frac{ME}{z})^2}   (b)  

We can use as an estimator for p \hat p =0.5. And replacing into equation (b) the values from part a we got:

n=\frac{0.5(1-0.5)}{(\frac{0.05}{1.96})^2}=384.16  

And rounded up we have that n=385

3 0
3 years ago
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