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inn [45]
2 years ago
7

On a zip-line course, you are harnessed to a cable that travels through the treetops. You start at Platform B and zip to the oth

er platform. What is the coordinate when you reach half way?
he midpoint between the Platform B and C is ( )
, ( )

Mathematics
1 answer:
lisov135 [29]2 years ago
4 0

The coordinates of the mid-point between points B and C is given by:

(-5, -10).

<h3>What is the mid-point concept?</h3>

The mid-point between two points is the halfway point between them, and is found using the mean of the coordinates.

The points in this problem are given as follows:

B(-40, -30), C(30, 10)

Hence the coordinates of the mid-point are:

  • x = (-40 + 30)/2 = -5.
  • y = (-30 + 10)/2 = -10.

More can be learned about the mid-point at brainly.com/question/10956693

#SPJ1

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Please HELP me!! Will choose brainliest (:
Rzqust [24]

Answer:

  yes

Step-by-step explanation:

There are several ways to go at this.

My first choice is to use a graphing calculator. It shows the function has a zero at x=5, so x-5 is a factor.

Another good choice is to use synthetic division (2nd attachment). If the remainder is zero, then x-5 is a factor. It is and it is.

__

You can also evaluate the function at x=5. The remainder theorem tells you that if the value is zero, then x-5 is a factor. Evaluating the polynomial written in Horner form is a lot like synthetic division.

  (((x -4)x -15)x +58)x -40 for x=5 is ... (-10·5 +58)5 -40 = 40-40 = 0

The value of h(5) is zero, so x-5 is a factor of h(x).

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3 years ago
When written in standard form, the product of (3+x) and (2x-5)
Mariulka [41]

Answer:

2x^2+x-15

Step-by-step explanation:

6x-15+2x^2-5x

2x^2+x-15

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3 years ago
Find an equation in rectangular coordinates for the cylindrical equation r = 2sintheta
frutty [35]

Answer:

x^2+(y-1)^2=1

Step-by-step explanation:

The given cylindrical equation is

r=2\sin \theta

Multiply both sides by r.

r^2=2r\sin \theta           .... (1)

The required formulas are

x=r\cos \theta,y=r\sin \theta,r^2=x^2+y^2

Substitute r\sin \theta =y,r^2=x^2+y^2 in equation (1).

x^2+y^2=2y

x^2+y^2-2y=0

Add 1 on both sides.

x^2+(y^2-2y+1)=1

(x-0)^2+(y-1)^2=1^2                    [\because (a-b)^2=a^2-2ab+b^2]

It is the equation of a circle centered at (0,1) with radius 1.

Therefore, the equation in rectangular coordinates is x^2+(y-1)^2=1.

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4 years ago
Please help it’s due right now
Yuki888 [10]

Answer: hey I actually just finished learning about this in math.

Step-by-step explanation: the graph is a function, because it passes the vertical line test

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