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2 years ago

B is the set of odd numbers greater than 5 and less than 21

Mathematics

1 answer:

butalik [34]2 years ago

7 0

Answer:

List method: {7,9,11,13,15,17,19}

Set method: {X:N where N is odd, N>5 and N<21}

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What is the area of these

Radda [10]

Answer:

Step-by-step explanation:

4 0

3 years ago

( 19, 6), (15. 16). what is the slope?

Brrunno [24]

Answer:

-5/2

to find slope you have to do y2-y1 over x2-x1 so it would be

16-6/15-19 ect.

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3 years ago

Which of the following

Archy [21]

The answer you are looking for is 36.

If you line up the numbers numerically (4, 8, 16, 32, 36, 64), you'll see that there's a pattern. Each number, multiplied by 2, gets the next number in the sequence. 4 * 2 = 8, 8 * 2 = 16, 16 * 2 = 32, and 32 * 2 = 64.

Thus meaning 36 is the odd number out. I hope this helps!

6 0

4 years ago

Read 2 more answers

<img src="https://tex.z-dn.net/?f=%5Csqrt%7B225%7D" id="TexFormula1" title="\sqrt{225}" alt="\sqrt{225}" align="absmiddle" class

Elza [17]

Answer:

Step-by-step explanation:

sqr root 225 = 15

7 0

3 years ago

Read 2 more answers

3. Your body mass index (BMI) is your weight in kilograms divided by the square of your height in meters. Many online BMI calcul

Anni [7]

Answer:

a) $P(X$

And we can find this probability using the normal standard table or excel and we got:

$P(Z$

That correspond to approximate 6.44%

b) $P(X>31)=P(\frac{X-\mu}{\sigma}>\frac{31-\mu}{\sigma})=P(Z>\frac{31-26.3}{5.4})=P(Z>0.87)$

And we can find this probability using the normal standard table or excel and we got:

$P(Z>0.87)=1-P(Z$

That correspond to approximate 19.2%

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".

Part a

Let X the random variable that represent the BMI of a population, and for this case we know the distribution for X is given by:

$X \sim N(26.3,5.4)$

Where $\mu=26.3$ and $\sigma=5.4$

We are interested on this probability

$P(X$

And the best way to solve this problem is using the normal standard distribution and the z score given by:

$z=\frac{x-\mu}{\sigma}$

If we apply this formula to our probability we got this:

$P(X$

And we can find this probability using the normal standard table or excel and we got:

$P(Z$

That correspond to approximate 6.44%

Part b

We are interested on this probability

$P(X>31)$

And the best way to solve this problem is using the normal standard distribution and the z score given by:

$z=\frac{x-\mu}{\sigma}$

If we apply this formula to our probability we got this:

$P(X>31)=P(\frac{X-\mu}{\sigma}>\frac{31-\mu}{\sigma})=P(Z>\frac{31-26.3}{5.4})=P(Z>0.87)$

And we can find this probability using the normal standard table or excel and we got:

$P(Z>0.87)=1-P(Z$

That correspond to approximate 19.2%

7 0

3 years ago