All categories

3 years ago

A science fair poster is a rectangle 4 feet long and 3 feet wide. What is the area of the poster in square inches?

Mathematics

1 answer:

a_sh-v [17]3 years ago

5 0

Answer:

Area of the poster is $1728$ square inches.

Step-by-step explanation:

First let's convert feet into inches.

1 feet = 12 inches

Length of the poster in inches:

$4$ feet = $4*12$ inches

= $48$ inches

Width of the poster in inches :

$3$ feet = $3*12$ inches

= $36$ inches

Area of a rectangle = Length * Width

Area of the poster = $48*36$

= $1728$ square inches

You might be interested in

What is the value of 12 more than the quiotent of a number of and two decreased by 4 when n is 4

liberstina [14]

Answer:

Step-by-step explanation:

"12 more than the quiotent of a number n of and two decreased by 4"

$\left(\dfrac{n}{2}-4\right)+12$

Simplify:

$\left(\dfrac{n}{2}-4\right)+12=\dfrac{n}{2}-4+12=\dfrac{n}{2}+8$

Put n = 4 to the expresssion:

$\dfrac{4}{2}+8=2+8=10$

4 0

4 years ago

Which is the directrix of a parabola with equation x2 = 8y?

olga_2 [115]

Answer:

Y=-2

Step-by-step explanation:

You would use the vertex form to find the directrix

4 0

3 years ago

OUCH MY BRAIN IS HURTING AFTER TRYING TO SOLVE THIS QUESTION

maria [59]

300° CCW is the same as 60° CW. N will show up where H is now.

The 3rd selection is appropriate.

4 0

3 years ago

Given that cos (x) = 1/3, find sin (90 - x)

drek231 [11]

$\sin{(A - B)} \equiv \sin{A}\cos{B} - \cos{A}\sin{B} \\\\
\therefore \sin{(90 - x)}\\
 = \sin{(90)}\cos{(x)} - \cos{(90)}\sin{(x)} \\
= (1)\cos{(x)} - (0)\sin{(x)} \\
= \cos{x} - 0 \\
= \cos{x} \\
= \frac{1}{3}
$

3 0

3 years ago

Read 2 more answers

Help me pleaseeeeeeeee

solniwko [45]

C. None of the x-values repeat.

4 0

3 years ago

Read 2 more answers