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1 year ago

Write an expression for cotA

Mathematics

2 answers:

mestny [16]1 year ago

7 0

Answer:

$cotA=\frac{2x}{5}$

Step-by-step explanation:

natulia [17]1 year ago

6 0

Answer:

$\text{cotA} =\frac{2x}{5}$

Step-by-step explanation:

cotA = (Adjacent side) ÷ (Opposite side)

The measure of the Adjacent side = 2x

The measure of the Opposite side = 5

Then

$\text{cotA} =\frac{2x}{5}$

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Please help urgently

Andreyy89

Hey there!

2ab + 2 / 2ab - 2

= 2(1)(3) + 2 / 2(1)(3) - 2

= 2(3) + 2 / 2(3) - 2

= 6 + 2 / 6 - 2

= 8 / 4

= 2

Therefore, your answer should be: 2

Good luck on your assignment & enjoy your day!

~Amphitrite1040:)

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11 months ago

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o-na [289]

Answer:

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3 years ago

A real estate agent has 19 properties that she shows. She feels that there is a 30% chance of selling any one property during a

netineya [11]

Answer:

$P(X \geq 5)=1-P(X$

We can find the individual probabilities:

$P(X=0)=(19C0)(0.3)^0 (1-0.3)^{19-0}=0.00114$

$P(X=1)=(19C1)(0.3)^1 (1-0.3)^{19-1}=0.0092$

$P(X=2)=(19C2)(0.3)^2 (1-0.3)^{19-2}=0.0358$

$P(X=3)=(19C3)(0.3)^3 (1-0.3)^{19-3}=0.0869$

$P(X=4)=(19C4)(0.3)^4 (1-0.3)^{19-4}=0.1491$

And replacing we got:

$P(X \geq 5) = 1-[0.00114+0.009282+0.0358+0.0869+0.149]= 0.7178$

Step-by-step explanation:

Previous concepts

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".

Solution to the problem

Let X the random variable of interest, on this case we now that:

$X \sim Binom(n=19, p=0.3)$

The probability mass function for the Binomial distribution is given as:

$P(X)=(nCx)(p)^x (1-p)^{n-x}$

Where (nCx) means combinatory and it's given by this formula:

$nCx=\frac{n!}{(n-x)! x!}$

And we want to find this probability:

$P(X \geq 5)$

And we can use the complement rule:

$P(X \geq 5)=1-P(X$

We can find the individual probabilities:

$P(X=0)=(19C0)(0.3)^0 (1-0.3)^{19-0}=0.00114$

$P(X=1)=(19C1)(0.3)^1 (1-0.3)^{19-1}=0.0092$

$P(X=2)=(19C2)(0.3)^2 (1-0.3)^{19-2}=0.0358$

$P(X=3)=(19C3)(0.3)^3 (1-0.3)^{19-3}=0.0869$

$P(X=4)=(19C4)(0.3)^4 (1-0.3)^{19-4}=0.1491$

And replacing we got:

$P(X \geq 5) = 1-[0.00114+0.009282+0.0358+0.0869+0.149]= 0.7178$

4 0

3 years ago

Please help and thank you

Mariana [72]

Answer:

B. l = (S - πr^2) / πr

Step-by-step explanation:

S = πrl + πr^2 solve for l

πrl = S - πr^2

l = (S - πr^2) / πr

Answer is B. l = (S - πr^2) / πr

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3 years ago

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Ningbo Shipping has issued preferred stock at its $125 per share par value. The stock will pay a $15 annual dividend. The cost o

katen-ka-za [31]

Answer:

The cost of Ningbo Shipping Preferred stock is 12.40%

Step-by-step explanation:

In this question, we are asked to calculate the cost of Ningbo shipping Preferred stock.

To calculate this, we make use of the following mathematical relation;

The cost preferred stock Kp = Annual dividends/ Issued price-Cost of Issuing

From the question, we identify the following;

Issued price = $125

Annual dividend = $15

Cost of Issuing = $4

Inserting these into the formula we have;

Kp = $15/$125 - $4 = 12.40%

This means that Cost of Ningbo shipping preferred stock is 12.40%

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2 years ago