Question

A linear function contains these points: (0,-1) & (3,8)

Answer 1

Answer:

slope: 3

y-intercept: (0, -1)

Find slope:

$\sf slope : \dfrac{y_2 - y_1}{x_2- x_1} = \dfrac{\triangle y}{\triangle x} \ \ \ where \ (x_1 , \ y_1), ( x_2 , \ y_2) \ are \ points$

Here given points are: (0, -1), (3, 8)

$\rightarrow \sf slope : \dfrac{8-(-1)}{3-0} = \dfrac{9}{3} = 3$

When finding y-intercept, the value of x is 0. Here given y is -1 when x is 0.

y-intercept: -1  or  (0, -1)

Answer 2

SOLVING

$\Large\maltese\underline{\textsf{A. What is Asked}}$

If a linear function contains these points: (0,-1) and (3,8), what is its slope and y-int.?

$\Large\maltese\underline{\textsf{B. This problem has been solved!}}$

Formula utilised, here $\bf{\dfrac{y2-y1}{x2-x1}}$.

Put in the values,

$\bf{\dfrac{8-(-1)}{3-0}}$  | subtract on top and bottom

$\bf{\dfrac{9}{3}}$ | divide on top and bottom

$\bf{3}$

The y-intercept is the second co-ordinate of the point (0,-1)

$\bf{Which\;is\;-1}$.

$\cline{1-2}$

$\bf{Result:}$

                      $\bf{\begin{cases} \bf{Slope=3} \\ \bf{Y-int. -1} \end{cases}$

$\LARGE\boxed{\bf{aesthetic\not1 \theta l}}$