15/4
how many times does 4 go into 15 without going over.....that would be 3 times....so 3 is ur whole number. 3 * 4 = 12......15 - 12 = 3...and 3 is ur numerator....the denominator stays the same
so ur answer is : 3 3/4
A=lw A=370 l=6w-23
370=w(6w-23)
6w^2-23w=370
6w^2-23w-370
Works out to
(W-10) pick this one
+10
W=10
or
(6w+37) is not the answer to choose
-37
6w=-37
/6 /6
W=-6.17
A) 10
B) 10
C) 37
Answer:
y = 27
Step-by-step explanation:
if x = 10 when y = 540 , y = 54x
if x = 1/2 y = 54*1/2 = 27
y = 27
We're going to be using combination since this question is asking how many different combinations of 10 people can be selected from a set of 23.
We would only use permutation if the order of the people in the committee mattered, which it seems it doesn't.
Formula for combination:

Where
represents the number of objects/people in the set and
represents the number of objects/people being chosen from the set
There are 23 people in the set and 10 people being chosen from the set


Usually I would prefer solving such fractions by hand instead of a calculator, but factorials can result in large numbers and there is too much multiplication. Using a calculator, we get

Thus, there are 1,144,066 different 10 person committees that can be selected from a pool of 23 people. Let me know if you need any clarifications, thanks!
~ Padoru
Area = [radius^2 * 5 * sine (360/5)] / 2
area = [64 * 5 * 0.95106] / 2
area =
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152.1696
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