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allsm [11]
2 years ago
8

What are the solutions of the equation (x 2)2 – 2(x 2) – 15 = 0? use u substitution to solve.

Mathematics
1 answer:
koban [17]2 years ago
3 0

The solution of the equation is x=3 or x=-5.

Given that the equation is (x+2)²-2(x-+2)-15=0 and use u substitution method to solve.

Let's assume that the (x+2)=u.

The given equation is rewritten as u²-2u-15=0.

Factorize the quadratic equation by adding or subtracting two number that gives the sum of -2u and product 15u² as

u²-5u+3u-15=0

u(u-5)+3(u-5)=0

Taking out (u-5) as common and get

(u-5)(u+3)=0

Compare each equation with 0 and get

u-5=0 or u+3=0

u=5 or u=-3

Performing back substitution by substituting the values of u in x+2

when u=5 then x is

x+2=5

x=3

And when u=-3 then x is

x+2=-3

x=-5

Hence, the solutions of the (x+2)²-2(x-+2)-15=0 is x=3 and x=-5.

Learn about the substitution here brainly.com/question/12802700

#SPJ4

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MA_775_DIABLO [31]
15/4

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so ur answer is : 3 3/4
7 0
3 years ago
I want to pour a concrete slab in my backyard with an area of 370 ft2 to put a basketball goal. If the length of the slab is 23
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A=lw A=370 l=6w-23
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6w^2-23w-370
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(W-10) pick this one
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or
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8 0
3 years ago
X and y=540 when X=10, find y when x=1/2
soldier1979 [14.2K]

Answer:

y = 27

Step-by-step explanation:

if x = 10 when y = 540 ,  y = 54x

if x = 1/2 y = 54*1/2 = 27

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4 0
3 years ago
How many different 10 person committees can be selected from a pool of 23 people?
Salsk061 [2.6K]

We're going to be using combination since this question is asking how many different combinations of 10 people can be selected from a set of 23.

We would only use permutation if the order of the people in the committee mattered, which it seems it doesn't.

Formula for combination:

C(n,r)=\dfrac{n!}{(n-r)!r!}

Where n represents the number of objects/people in the set and r represents the number of objects/people being chosen from the set

There are 23 people in the set and 10 people being chosen from the set

C(23,10)=\dfrac{23!}{(23-10)!10!}

=\dfrac{23!}{13!\times10!}

Usually I would prefer solving such fractions by hand instead of a calculator, but factorials can result in large numbers and there is too much multiplication. Using a calculator, we get

=1,144,066

Thus, there are 1,144,066 different 10 person committees that can be selected from a pool of 23 people. Let me know if you need any clarifications, thanks!

~ Padoru

4 0
3 years ago
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4 0
3 years ago
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