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allsm [11]
2 years ago
8

What are the solutions of the equation (x 2)2 – 2(x 2) – 15 = 0? use u substitution to solve.

Mathematics
1 answer:
koban [17]2 years ago
3 0

The solution of the equation is x=3 or x=-5.

Given that the equation is (x+2)²-2(x-+2)-15=0 and use u substitution method to solve.

Let's assume that the (x+2)=u.

The given equation is rewritten as u²-2u-15=0.

Factorize the quadratic equation by adding or subtracting two number that gives the sum of -2u and product 15u² as

u²-5u+3u-15=0

u(u-5)+3(u-5)=0

Taking out (u-5) as common and get

(u-5)(u+3)=0

Compare each equation with 0 and get

u-5=0 or u+3=0

u=5 or u=-3

Performing back substitution by substituting the values of u in x+2

when u=5 then x is

x+2=5

x=3

And when u=-3 then x is

x+2=-3

x=-5

Hence, the solutions of the (x+2)²-2(x-+2)-15=0 is x=3 and x=-5.

Learn about the substitution here brainly.com/question/12802700

#SPJ4

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Plzz help me with this question​
Aleks04 [339]

Answer: 45

Step-by-step explanation:

Complemntary angles result in a sum of 90. So, H=45 means

45+J=90

90-45= 45

6 0
3 years ago
ABC and EDC are straight lines. EA is parallel to DB. EC = 8.1 cm. DC = 5.4 cm. DB = 2.6 cm. (a) Work out the length of AE. cm (
harkovskaia [24]

By applying the knowledge of similar triangles, the lengths of AE and AB are:

a. \mathbf{AE = 3.9 $ cm}\\\\

b. \mathbf{AB = 2.05 $ cm} \\\\

<em>See the image in the attachment for the referred diagram.</em>

<em />

  • The two triangles, triangle AEC and triangle BDC are similar triangles.
  • Therefore, the ratio of the corresponding sides of triangles AEC and BDC will be the same.

<em>This implies that</em>:

  • AC/BC = EC/DC = AE/DB

<em><u>Given:</u></em>

EC = 8.1 $ cm\\\\DC = 5.4 $ cm\\\\DB = 2.6 cm\\\\AC = 6.15 $ cm

<u>a. </u><u>Find the length of </u><u>AE</u><u>:</u>

EC/DC = AE/DB

  • Plug in the values

\frac{8.1}{5.4} = \frac{AE}{2.6}

  • Cross multiply

5.4 \times AE = 8.1 \times 2.6\\\\5.4 \times AE = 21.06

  • Divide both sides by 5.4

AE = \frac{21.06}{5.4} = 3.9 $ cm

<u>b. </u><u>Find the length of </u><u>AB:</u>

AB = AC - BC

AC = 6.15 cm

To find BC, use AC/BC = EC/DC.

  • Plug in the values

\frac{6.15}{BC} = \frac{8.1}{5.4}

  • Cross multiply

BC \times 8.1 = 6.15 \times 5.4\\\\BC = \frac{6.15 \times 5.4}{8.1} \\\\BC = 4.1

  • Thus:

AB = AC - BC

  • Substitute

AB = 6.15 - 4.1\\\\AB = 2.05 $ cm

Therefore, by applying the knowledge of similar triangles, the lengths of AE and AB are:

a. \mathbf{AE = 3.9 $ cm}\\\\

b. \mathbf{AB = 2.05 $ cm} \\\\

Learn more here:

brainly.com/question/14327552

3 0
3 years ago
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Rudik [331]
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8 0
3 years ago
{y=-x+1<br> {y=4x-14<br> please help me <br> my paper is due today
Temka [501]

- x + 1 = 4x - 14 \\  - x - 4x =  - 14 - 1 \\  - 5x =  - 15 \\ x = 3

Substitute x = 3 in any given equations. I will do in y = - x + 1

y =  - x + 1 \\ y =  - 3 + 1 \\ y =  - 2

Therefore the answer is (3,-2)

7 0
3 years ago
You randomly choose one of the tiles. Without replacing the first tile, you choose a second tile. Find the probability of the co
Volgvan
Choosing the first tile:

At first, there are 7 tiles.
You are interested in choosing a 5. There is only one tile with a 5.
p(5) = 1/7


Choosing the second tile:
After the 5 has been taken, now there are 6 tiles left.
Only one tile has the number 6.
p(6) = 1/6

The overall probability of choosing a 6 after a 5 is the product of the individual probabilities:

p( 5 then 6) = 1/7 * 1/6 = 1/42

Answer: The probability of choosing a 5 and then a 6 is 1/42.
8 0
3 years ago
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