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Korolek [52]
3 years ago
7

Sixty percent of Company A’s employees are considered top performers. Fifty five percent of Company A’s employees are in a rigor

ous training program. Assuming these two statements are true are most of Company A’s employees in the rigorous training program considered top performers?
Mathematics
2 answers:
777dan777 [17]3 years ago
6 0

Answer:33 %

Step-by-step explanation:

Given

60 % of company A's employees are considered  top performer

55 % of company A's employee are in a rigorous training program.

Now Company A's employees in the rigorous training program considered top performer are 0.60\times 0.55=0.33

That is 33 % of employee is in rigorous training and top performers.

pickupchik [31]3 years ago
5 0
Not exactly. there are still 40 percent of the employees that are not top performers. for all you know those 40 percent could make up the majority of the employees in the training program<span />
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We can rewrite the expression under the radical as

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then taking the fourth root, we get

\sqrt[4]{\left(\dfrac32a^2b^3c^4\right)^4}=\left|\dfrac32a^2b^3c^4\right|

Why the absolute value? It's for the same reason that

\sqrt{x^2}=|x|

since both (-x)^2 and x^2 return the same number x^2, and |x| captures both possibilities. From here, we have

\left|\dfrac32a^2b^3c^4\right|=\left|\dfrac32\right|\left|a^2\right|\left|b^3\right|\left|c^4\right|

The absolute values disappear on all but the b term because all of \dfrac32, a^2 and c^4 are positive, while b^3 could potentially be negative. So we end up with

\dfrac32a^2\left|b^3\right|c^4=\dfrac32a^2|b|^3c^4

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dezoksy [38]
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A business assistant must leave more than $60 in the supply account. There is $650 in the account. The assistant needs to order
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Answer:

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Step-by-step explanation:

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o-na [289]
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Please help..not too sure on how to work this out.
lina2011 [118]

Answer and Step-by-step explanation:

Ok, it's basically just parts of a circle circumference and area equation. Let's start first by writing down both equations.

C = 2πr

C = πd

A = πr^{2}

Now, all we have to do is plug in the values into those equations!

4. C = 2π(12)                  A = π(12^{2})

r = 12

d = 24     <---- (12 times 2 equals 24)

C = 24π

A = 144π   <---- (12 times 12 (itself) equals 144)

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d = 4.8

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6.  20π = 2πr                  A = πr^{2}

r = 10            <------- (20π divided by π and divided by 2)

d = 20          <------- (20π divided by π)

C = 20π

A = 100π    <------- (10 times 10 equals 100)

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r = 9            <------- (81π divided by π and square rooted equals 9)

d = 18          <------- (9 times 2 equals 18)

C = 18π      <------- (2 times 9 equals 18, times π)

A = 81π

#teamtrees #WAP (Water And Plant) #ELM (Every Life Matters)

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