You could get a laptop for like 200 that could run well and enough space for stuff.
The correct answer of the given question above would be option D. A wet-carpet cleaner that carries it's own water supply has water pressure created by a MOTOR-DRIVE PUMP. T<span>his product is easy to use, strong, and highly durable. Hope this answers your question. Have a great day!</span>
Answer:
a=input("Amount in pennies")
b=int(a)
dollars=0
dimes= 0
quarters=0
nickels=0
pennies = 0
dollars = int(b/100)
b= b- dollars *100
quarters=int(b/25)
b=b-quarters*25
dimes = int(b/10)
b = b -dimes*10
nickels=int(b/5)
b=b - nickels * 5
pennies = b
print(dollars)
print(dimes)
print(nickels)
print(pennies)
Explanation:
The required program is in answer section. Note, the amount is entered in pennies.
Answer:
The program is written using PYTHON SCRIPT below;
N=int(input(" Enter number of Rows you want:"))
M=[] # this for storing the matrix
for i in range(N):
l=list(map(int,input("Enter the "+str(i+1)+" Row :").split()))
M.append(l)
print("The 2D Matrix is:\n")
for i in range(N):
print(end="\t")
print(M[i])
W=[] # to store the first non zero elemnt index
T=[] # to store that value is positive or negative
L=len(M[0])
for i in range(N):
for j in range(L):
if (M[i][j]==0):
continue
else:
W.append(j) # If the value is non zero append that postion to position list(W)
if(M[i][j]>0): #For checking it is positive or negative
T.append(+1)
else:
T.append(-1)
break
print()
print("The first Non Zero element List [W] : ",end="")
print(W)
print("Positive or Negative List [T] : ",end="")
print(T)
Explanation:
In order for the program to determine a set of test cases it takes in input of 2D matrix in an N numbet of rows.
It goes ahead to program and find the column index of the first non-zero value for each row in the matrix A, and also determines if that non-zero value is positive or negative. The If - Else conditions are met accordingly in running the program.
