Answer:
True
Explanation:
It is TRUE that An Information System is the set of steps that need to be followed to ensure that software development proceeds in an orderly fashion.
This is evident in the fact that the Information system involves various stages and different elements such as data, people, procedures, hardware, and software.
All these elements form together to create several steps in software development in a suitable manner that meets the clients' and customers' needs.
Answer:
The main implication of the price elasticity in the various technology products may lead increase the productivity of the products as customers buy more products due to the cheaper price of the product.
as die to the time lower costs will prompt higher deals volumes, which may compensate for the lower overall revenue. Now and again, raising the cost of your item or administration will prompt higher overall revenues yet will bring down your business volumes.
It also offer many advantages like high reliability, security and the scalability.
A sixteen bit microprocessor chip used in early IBM PCs. The Intel 8088 was a version with an eight-bit externaldata bus.
The Intel 8086 was based on the design of the Intel 8080 <span>and </span>Intel 8085 (it was source compatible with the 8080)with a similar register set, but was expanded to 16 bits. The Bus Interface Unit fed the instruction stream to theExecution Unit through a 6 byte prefetch queue, so fetch and execution were concurrent - a primitive form ofpipelining (8086 instructions varied from 1 to 4 bytes).
It featured four 16-bit general registers, which could also be accessed as eight 8-bit registers, and four 16-bit indexregisters (including the stack pointer). The data registers were often used implicitly by instructions, complicatingregister allocation for temporary values. It featured 64K 8-bit I/O (or 32K 16 bit) ports and fixed vectored interrupts.There were also four segment registers that could be set from index registers.
The segment registers allowed the CPU to access 1 meg of memory in an odd way. Rather than just supplyingmissing bytes, as most segmented processors, the 8086 actually shifted the segment registers left 4 bits and addedit to the address. As a result, segments overlapped, and it was possible to have two pointers with the same valuepoint to two different memory locations, or two pointers with different values pointing to the same location. Mostpeople consider this a brain damaged design.
Although this was largely acceptable for assembly language, where control of the segments was complete (it couldeven be useful then), in higher level languages it caused constant confusion (e.g. near/far pointers). Even worse, thismade expanding the address space to more than 1 meg difficult. A later version, the Intel 80386, expanded thedesign to 32 bits, and "fixed" the segmentation, but required extra modes (suppressing the new features) forcompatibility, and retains the awkward architecture. In fact, with the right assembler, code written for the 8008 canstill be run on the most <span>recent </span>Intel 486.
The Intel 80386 added new op codes in a kludgy fashion similar to the Zilog Z80 and Zilog Z280. The Intel 486added full pipelines, and clock doubling (like <span>the </span>Zilog Z280).
So why did IBM chose the 8086 series when most of the alternatives were so much better? Apparently IBM's own engineers wanted to use the Motorola 68000, and it was used later in the forgotten IBM Instruments 9000 Laboratory Computer, but IBM already had rights to manufacture the 8086, in exchange for giving Intel the rights to its bubble memory<span> designs.</span> Apparently IBM was using 8086s in the IBM Displaywriter word processor.
Other factors were the 8-bit Intel 8088 version, which could use existing Intel 8085-type components, and allowed the computer to be based on a modified 8085 design. 68000 components were not widely available, though it could useMotorola 6800 components to an <span>extent.
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Hope this helps
Answer:
i think its new
Explanation:
if this is incorrect i apologize
Complete Question:
Write statements that output variable numComputers as follows. End with a newline. There are 10 computers.
#include <iostream>
using namespace std;
int main()
{
int numComputers;
cin >> numComputers; // Program will be tested with values: 10.
...
return 0;
}
Answer:
cout << "There are ";
cout << numComputers;
cout << " computers." << "\n";
Explanation:
Using three cout statements the string "There are 10 computers." is printed out, notice that the variable numComputers is entered by the user when the program is run. Another way of concatenating an integer variable and string for printout is by the use of the + (plus) operator.
