All categories

2 years ago

-2+12-2^3 divided by 2^0 times 3

Mathematics

1 answer:

nikklg [1K]2 years ago

6 0

Answer:

The correct answer is -14

Step-by-step explanation:

You might be interested in

Given the expression 12 over 12 to the third power.

4vir4ik [10]

Part 1:
Before we begin, you need to remember the following rule:
$\frac{x^a}{x^b} = x^{a-b}$

The given expression is:
$\frac{12}{12^3}$

Since the base is the same in both numerator and denominator, we can apply the above rule. This means that:
$\frac{12}{12^3}$ = 12¹⁻³ = 12⁻²

Part 2:
Before we begin, you need to remember the following rule:
x⁻ᵃ = $\frac{1}{x^a}$

Now, from part 1, we simplified the expression into 12⁻²
Since the power is negative, we can apply the above rule.
This means that:
12⁻² = $\frac{1}{(12)^2} = \frac{1}{12*12} = \frac{1}{144}$

Hope this helps :)

5 0

4 years ago

Read 2 more answers

(-1, 4) and (1,-1) And (0,-8) and 3,2)

Free_Kalibri [48]

Answer:

These are all points on a graph. I'm not sure what you're asking.

7 0

4 years ago

A recent survey by the American Automobile Association showed that a

vichka [17]

Answer:

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

I need help with this

Kruka [31]

Answer:

X=9/4

Step-by-step explanation:

-3x+10=5x-8

Subtract 10 from each sides

-3x=5x-18

Subtract 5x from both sides

-8x=-18

Divide both sides by -8

x=9/4

I hope this helped

3 0

3 years ago

X^2 - 9x -10 =0 has a discriminant of: a. 121 b. 72 c. -359 d. 41 e. 136

Feliz [49]

In the standard form of quadratic
$ax^{2} +bx+c$
the discriminant is
$b^{2} -4ac$
In your quadratic, a = 1, b = -9 and c = -10
Now you need to plug these values into the expression for the discriminant.

7 0

3 years ago