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Lilit [14]
2 years ago
7

-2+12-2^3 divided by 2^0 times 3

Mathematics
1 answer:
nikklg [1K]2 years ago
6 0

Answer:

The correct answer is <u>-14</u>

Step-by-step explanation:

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The Chang family is on
xeze [42]
I think is d correct answer 60%
4 0
3 years ago
Find the terminal point on the unit circle determined by 11pi/6 radiants
irga5000 [103]

Answer:

(\frac{\sqrt{3}}{2},-\frac{1}{2})

Step-by-step explanation:

The unit circle has the parametric equation:

x=\cos \theta

y=\sin \theta

where \theta=\frac{11\pi }{6} in our case is the terminal side of the angle in standard position.

We substitute to get:

x=\cos \frac{11\pi }{6}=\frac{\sqrt{3}}{2}

y=\sin \frac{11\pi }{6}=-\frac{1}{2}

\therefore (\frac{\sqrt{3}}{2},-\frac{1}{2}) is the required point.

6 0
3 years ago
Given a rectangle with an area of 20 square units, if the width is x units and the length is x + 1 units, what is the difference
ollegr [7]

Answer: 1unit.

Step-by-step explanation:

Area of the rectangle

A = length × width

Since the area = 20 and the width is x and the length is x + 1.

We now substitute for the values in the above formula and solve for x

20 = x × x + 1

20 = x( x + 1 ), we now open

20 = x² + x , then re arrange.

x² + x - 20 = 0, this is a quadratic equation.we solve for x using quadratic means

Here, I am going to solve using factorization by grouping

x² + x - 20 = 0

x² + 5x - 4x - 20 = 0

x( x + 5 ) - 4( x + 5 ) = 0

( x + 5 )( x - 4 ). = 0

Therefore, the solution for x will be

x = -5 or 4, but x can not be -5 ( negative), so x = 4.

Now the difference between width and the length can easily be calculated from the above,

Width = 4 (x) , and length = 5 (4 + 1),

Now difference will be

5 - 4 = 1unit.

5 0
3 years ago
If ef = 19 and fg = 12 then ef = ???
vesna_86 [32]
Ef=19, as given in the question.
4 0
3 years ago
PLEASE HELP ASAAAAPPPPPPP
ddd [48]
Distribute ^4 to both 2 and q^5

2^4 = 2 x 2 x 2 x 2 = 16
(q^5)^4 = q^20

16(q^20) = 16q^20 

16q^20 is your answer

hope this helps
3 0
3 years ago
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