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matrenka [14]
2 years ago
11

Please help ill give whoever answers the best the brainliest answer

Mathematics
2 answers:
Schach [20]2 years ago
8 0
The lowest graph is the answer. Why? Well, the others are incorrect because:

The 1st graph would represent a scenario where on the way home from school, Angelo is idle somewhere and then walks home at a faster rate than he did to school.

The 2nd graph would represent a scenario where Angelo walks at a faster pace to school than he does back home.

The 3rd graph would represent a scenario where on the way to school, Angelo becomes idle for a bit and then continues to walk to school at the same pace.

Meanwhile, the 4th graph represents Angelo walking to school, staying at school for a while, and then walking back home at a faster rate (possibly running).

Your final answer: The bottom graph is the correct answer. If you need help, let me know and I will gladly assist you.
ICE Princess25 [194]2 years ago
6 0
1. Walks slowly to school: rising line that slowly rising up
2. Stay at school the whole day: straight line for a period of time
3. Walks faster rate walking back home without stopping: descending line that quickly falls

It’s picture 2
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(a) One possibility is 8.45

Rounded to the nearest integer = 8

Rounded to the nearest tenth = 8.5

And rounding this to the nearest integer = 9

 

(b) The possible numbers are 8.45 to 8.49, inclusively

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3 years ago
A rectangle has been enlarged by a scale of 3.5
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4 years ago
A bone fragment has 67% of the parent Pb-210 remaining. The half-life of Pb-210 is 22 years. How old is the bone fragment?
Korolek [52]

To solve this question we will use two important formulas.

The first formula involves the calculation of the decay constant, k which is to be found as:

k=\frac{0.6931}{T_{\frac{1}{2}}}

where T_{\frac{1}{2}} is the half life of Pb-210 which is given to be 22 years in the question.

Thus, k=\frac{0.6931}{22}\approx0.0315

Now, we will use the second formula which is called the function of decay formula and is given as:

N = N_{0} e^{-kt}

where N percentage of Pb-210 remaining in the bone at present, which in our case is 67% or 0.67

N_{0} percentage of Pb-210 to start with, which is always 100% or 1.

Plugging in all these values in the decay formula we are supposed to find the time, t.

0.67=1\times e^{-0.0315t}

Taking natural log on both sides we get:

ln(0.67)=-0.0315t

\approx-0.4005=-0.0315t

\therefore t=\frac{0.4005}{0.0315}

t\approx12.71 years

Therefore the bone fragment is about 12.71 years old.

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4 years ago
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