Answer:
-7k = -45.5
Explanation:
You can solve this by plugging in the “k” to the problems that are listed.
If you were to plug 6.5 in for all those problems, you’d get:
-3(6.5) = -19.5
-1 + 6.5 = 5.5
-7(6.5) = -45.5
-2 + 6.5 = 4.5
So, in this case, looking at the ones I answered and looking at the problems listed, the correct answer would have to be -7k = -45.5.
Answer:

And solving we got:



Step-by-step explanation:
For this case we can define the following notation:
represent the width
And we want a maximum error of 0.0003 so we can set up the following equation:

And solving we got:



Answer:
Graph or the problem?
Step-by-step explanation:
The constant of proportionality k is given by k=y/x where y and x are two quantities that are directly proportional to each other. Once you know the constant of proportionality you can find an equation representing the directly proportional relationship between x and y, namely y=kx, with your specific k. (i looked up this explanation but not sure if it’s right.. if it’s wrong let me know:) )