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1 year ago

12

The volume of a fish tank is 50 cubic feet. if the density is 0.2 fish over feet cubed, how many fish are in the tank? 5 10 125

250

1 answer:

Agata [3.3K]1 year ago

4 0

Answer: 10

Step-by-step explanation:

I just took the test!! :)

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Help PLSS I NEEED IT NOWW

LiRa [457]

Answer: september 15 saplings, 43 saplings

Step-by-step explanation:

i need money, and i need it now! sorry, your question just reminded me of that commercial.

the least number of saplings was planted in September and it was 15 saplings.

now the second part of the question i added up all the saplings and got 520. divided by 12 months in the year is 43.333 rounded is 43 saplings

7 0

2 years ago

Helppp meeeeeee asappppppp

Juliette [100K]

Answer:

9.2

Step-by-step explanation:

So the 14 can be divided equally on both sides by the fact that the line cutting it at right angle bisects it.

Thus having 6 and 7 as the two shorter sides of a right angled triangle will help us get the radius( hypotenuse in this case) using the square root of the sum of the squares of both six and 7, the Pythagoras theory.

this leads to 9.2 as our answer

5 0

2 years ago

For the figures below, assume they are made of semicircles, quarter circles and squares. For each shape, find the area and perim

Marina86 [1]

Area of the shaded region $$=36(\pi -2)$ square cm

Perimeter of the shaded region $=6 (\pi + 2\sqrt 2)$ cm

Solution:

Radius of the quarter of circle = 12 cm

Area of the shaded region = Area of quarter of circle – Area of the triangle

$$=\frac{1}{4} \pi r^2 - \frac{1}{2} bh$

$$=\frac{1}{4} \pi \times 12^2 - \frac{1}{2} \times 12 \times 12$

$$=36\pi -72$

$$=36(\pi -2)$ square cm.

Area of the shaded region $$=36(\pi -2)$ square cm

Using Pythagoras theorem,

$AC^2=AB^2+BC^2$

$AC^2=12^2+12^2$

$AC^2=288$

Taking square root on both sides of the equation, we get

$AC= 12\sqrt 2$ cm

Perimeter of the quadrant of a circle = $\frac{1}{4} \times 2\pi r$

$$=\frac{1}{4} \times 2 \times \pi \times 12$

$$=6 \pi$ cm

Perimeter of the shaded region = $6 \pi + 12\sqrt 2$ cm

$=6 (\pi + 2\sqrt 2)$ cm

Hence area of the shaded region $$=36(\pi -2)$ square cm

Perimeter of the shaded region $=6 (\pi + 2\sqrt 2)$ cm

6 0

2 years ago

What's the answer? The question is change 425,000 mL to L

PilotLPTM [1.2K]

425L, you have to move the decimal place three places to the left.

3 0

2 years ago

Read 2 more answers

10.) For the natural logarithm function, determine the point on the curve where its associated tangent line passes through the

Lunna [17]

f(x)=lnx

y=f(x)

dy/dx= 1/x

tangent at (x,y) has slope 1/x

eqn of tangent is y = mx + c

since the tangent passes through origin, c=0

substitute y = lnx and m= 1/x to above eqn

lnx = 1

x=e

y=lne=1

4 0

2 years ago