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Dmitrij [34]
2 years ago
13

the area of the curved surface of a solid cylinder is equal to 2/3 of the total area of the same cylinder . If the total surface

of the cylinder is 924 sq.cm, find the radius and height of the cylinder.​
Mathematics
1 answer:
zheka24 [161]2 years ago
7 0

Answer:

Sa = 36 circumference per meter square

This answer is wrong sorry

Will you my friend

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Arrange the pairs of points in increasing order of the slopes of the lines joining them. (15, 30) and (20, 40)
gavmur [86]

Answer: m1 = 0.5

M2= 0.375

M3 = 2.25

M4 = 3.0

M5 = 13.5

M6 = 0.285

M7 = 7.0

Step-by-step explanation:

(20,40)-(15,30)=(5,10), m1=5/10=0.5

(18,48)-(12,32)=(6,16), m2=3/8=0.375

(72,32)-(27,12)=(45,20), m3=9/4=2.25

(60,20)-(45,15)=(15,5), m4=3.0

(243,18)-(27,2)=(216,16), m5=27/2=13.5

(24,84)-(18,63)=(6,21), m6=2/7=0.285...

(84,12)-(63,9)=(21,3), m7=7.0

4 0
3 years ago
Solve x - 6x = 40 by factoring. What is<br> the solution?
marta [7]

Answer:

x=-8

Step-by-step explanation:

collect like terms

-5x=40

divide both sides of the equation by -5

so the answer would be x=-8

7 0
3 years ago
Burn is to ointment as grief is to
Nitella [24]

Answer:The answer is Sympathy

Step-by-step explanation:

4 0
3 years ago
Un submarino se encuentra 50m por debajo del nivel del mar y comienza a subir 2m cada 5 minutos ¿a que profundidad se encuentra
Trava [24]

Answer:

a) El submarino se encuentra a una profundidad de 26 metros una hora después de haber comenzado el ascenso.

b) Al submarino le falta 1 hora y 5 minutos para llegar a la superficie.

Step-by-step explanation:

a) De acuerdo con el enunciado, la cantidad de metros ascendidos por el submarino es directamente proporcional al tiempo, entonces la profundidad del submarino a la hora de haber comenzado el ascenso se obtiene mediante la siguiente relación lineal:

h = 50\,m - \frac{2\,m}{5\,min}\times 60\,min

h = 26\,m

El submarino se encuentra a una profundidad de 26 metros una hora después de haber comenzado el ascenso.

b) En primer lugar, calculamos el tiempo total del viaje mediante la siguiente relación:

\frac{2\,m}{5\,min} = \frac{50\,m}{t}

t = 50\,m\times \frac{5\,min}{2\,m}

t = 125\,min (2\,h\,5\,min)

El tiempo faltante para alcanzar la superficie se calcula mediante la siguiente sustracción:

\Delta t = 125\,min - 60\,min

\Delta t = 65\,min (1\,h\,5\,min)

Al submarino le falta 1 hora y 5 minutos para llegar a la superficie.

7 0
3 years ago
Can someone please help me?
Reika [66]
The answer is -2 because the the next one is -3
8 0
3 years ago
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