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nevsk [136]
2 years ago
12

Triangle A E C is shown. Line segment B D is drawn near point C to form triangle B D C.

Mathematics
1 answer:
AVprozaik [17]2 years ago
3 0

∠BDC and ∠AED are right angles, is  a piece of additional information is appropriate to prove △ CEA ~ △ CDB

Triangle AEC is shown. Line segment B, D is drawn near point C to form triangle BDC.

<h3> What are Similar triangles?</h3>

Similar triangles, are those triangles which have similar properties,i.e. angles and proportionality of sides.

Image is attached below,
as shown in figure
∡ACE = ∡BCD ( common angle )
∡AED = ∡BDC ( since AE and BD are perpendicular to same line EC and make right angles as E and C)
∡EAC =- ∡DBC ( corresponding angles because AE and BD are parallel lines)

Thus, △CEA ~ △CDB , because of the two perpendiculars AE and BD.

Learn more about similar triangles here:
brainly.com/question/25882965

#SPJ1


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F(x)=Tan^-1 (1)<br><br> PLEASE ANSWER! WILL GIVE BRAINLIEST
notka56 [123]

Answer:

−π

----

4

Step-by-step explanation:

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Since the "Odds and Evens Identity" states that tan(-x) = -tan(x). Tan(-1)= -pi/4.

Knowing that tan is negative in quadrants 2 and 4. the answer is in either of those two quadrants. BUT!!! since inverse of tan is restricted to quadrants 1 and 4 we are left with the only answer -pi/4.

5 0
3 years ago
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Ludmilka [50]
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3 0
3 years ago
What is the value of x in 145.95-2x=-4.05?
kotykmax [81]
145.95 - 2x = -4.05
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x = 75
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Hope this helps!!!!
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erastovalidia [21]

Answer:

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Step-by-step explanation:

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choose the equation below that represents the line passing through the point (−2, −3) with a slope of −6. y 3 = −6(x 2) y 2 = 6(
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