Triangle A E C is shown. Line segment B D is drawn near point C to form triangle B D C.
1 answer:
∠BDC and ∠AED are right angles, is a piece of additional information is appropriate to prove △ CEA ~ △ CDB
Triangle AEC is shown. Line segment B, D is drawn near point C to form triangle BDC.
Similar triangles, are those triangles which have similar properties,i.e. angles and proportionality of sides.
Image is attached below,
as shown in figure
∡ACE = ∡BCD ( common angle )
∡AED = ∡BDC ( since AE and BD are perpendicular to same line EC and make right angles as E and C)
∡EAC =- ∡DBC ( corresponding angles because AE and BD are parallel lines)
Thus, △CEA ~ △CDB , because of the two perpendiculars AE and BD.
Learn more about similar triangles here:
brainly.com/question/25882965
#SPJ1
You might be interested in
Answer:
a) P=0.03
b) α=0.05
c) 0.72
d) 100
e) 0.72
Step-by-step explanation:
a) The P-value is the probability of the sample result. In this case the P-value is 0.03.
b) The level of significance is the threshold of probabilty for the null hypothesis to be reejcted or not. It is contrasted with the P-value to know if the effect is significant. In this case, the level of significance is 0.05.
NOTE: if it is a two-side test, the level of significance is 0.1 (two times 0.05).
c) The sample proportion is the one that results from the sample data. In this case, the sample proportion is 0.72.
d) The sample size is the amount of consumers reported. In this case is 100 customers.
e) The null value is 0.72 (equal to the sample proportion), because it is tested if there is no difference between the population proportion and the sample proportion.