Begin with cos(θ) = 5/13, θ in Quadrant IV
you should distinguish the 5-12-13 right-angled triangle
and then cosØ = adjacent/hypotenuse
x = 5, r = 13 , y = -12, since Ø is in IV
and sinØ = -12/13
also tan(ϕ) = −√15 = -√15/1 = y/x and ϕ is in II,
y = √15 , x = -1
r^2 = x^2 + y^2 = 15+1 = 16
r = 4
sinϕ = √15/4 , cosϕ = -1/4
you must know that:
cos(θ − ϕ) = cosθcosϕ + sinθsinϕ
= (5/13)(-1/4) + (-12/13)(√15/4)
= -5/52 - 12√15/52
= (-5-12√15)/52
Answer:
The factored version of the given equation is going to be (3x² + 4y)(x + 5)
Step-by-step explanation:
<em>3x³ + 15x² + 4xy + 20y</em>
First, you break down 3x³. You can do this by finding the common factor of 3x³ and 15x². You can add the x to the other parentheses because x times x² equals x³
<em>(3x² + )(x + 5)</em>
Now, we break down 4xy by finding the common factor of 4xy and 20y.
<em>(3x² + 4y)(x + 5)</em>
So, the factored version of the equation above is (3x² + 4y)(x + 5)
Answer:
420 + 15 = 435
360 + 45 = 405
435 - 405 = 30.
30 minutes less sunlight
Step-by-step explanation:
