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tester [92]
2 years ago
8

Please I need the answer :-)​

Mathematics
1 answer:
Arturiano [62]2 years ago
5 0

Answer:

Step-by-step explanation:

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A,b,c, d that’s the answer
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Anon25 [30]
<h3>Answer: Choice D</h3>

=============================

Explanation:

The first figure has 4 sides (quadrilateral)

The second figure has 5 sides (pentagon)

The third figure has 6 sides (hexagon)

Each time we increase the number of sides by 1.

The fourth figure must have 7 sides (heptagon). The only thing that has 7 sides is the figure listed in choice D.

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3 years ago
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Seeds are often treated with fungicides to protect them in poor-draining, wet environments. A small-scale trial, involving six t
alukav5142 [94]

Answer:

0.0076 = 0.76% probability that all five plants emerged from treated seeds

Step-by-step explanation:

The plants were chosen without replacement, which means that the hypergeometric distribution is used to solve this question.

Hypergeometric distribution:

The probability of x successes is given by the following formula:

P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}

In which:

x is the number of successes.

N is the size of the population.

n is the size of the sample.

k is the total number of desired outcomes.

Combinations formula:

C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

In this question:

6 + 6 = 12 seeds, which means that N = 12

6 treated, which means that k = 6

Five sprouted, which means that n = 5

What is the probability that all five plants emerged from treated seeds?

This is P(X = 5). So

P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}

P(X = 5) = h(5,12,5,6) = \frac{C_{6,5}*C_{6,0}}{C_{12,5}} = 0.0076

0.0076 = 0.76% probability that all five plants emerged from treated seeds

3 0
3 years ago
I neeeeeed help really fast, please!! 0 X 0 = ?
Fiesta28 [93]
The answer is zero 0
6 0
3 years ago
Read 2 more answers
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