All categories

3 years ago

Question is attached.Step by step explanation only!

Mathematics

2 answers:

Arada [10]3 years ago

6 0

LHS

$\\ \sf\longmapsto \dfrac{cos(90-\Theta)}{sin\Theta}+\dfrac{sin\Theta}{cos(90-\Theta)}$

$\boxed{\sf cos(90-A)=sinA}$

$\\ \sf\longmapsto \dfrac{sin\Theta}{sin\Theta}+\dfrac{sin\Theta}{sin\Theta}$

$\\ \sf\longmapsto 1+1$

$\\ \sf\longmapsto 2$

Hence proved

Anna11 [10]3 years ago

4 0

Answer:

Attached is your answer.

Step-by-step explanation:

hence Proved.

Hope it helps you!!

You might be interested in

Write an equation of a line that is perpendicular to y = ½ x + 3 and passes through the point (10, -5).

Tresset [83]

Y=MX+B THEREFORE Y=-2X-5

4 0

4 years ago

Share £45 in the ratio 4:5

blsea [12.9K]

Answer:

20 : 25

Step-by-step explanation:

A : B : total

4 : 5 : 4+5 = 9

We want to share 45

45/9 = 5

Multiply each share by 5

A : B : total

4*5 : 5*5 : 9*5

20 : 25 : 45

6 0

3 years ago

Solve 2(4x – 3) = 2(x + 2) + 8 for x. A. x = –2 B. x = 4 C. x = 3 D. x = –5

kap26 [50]

Answer:

Step-by-step explanation:

Solve the equation by applying the distributive property and combine like terms. Then use inverse operations to isolate the variable.

2(4x – 3) = 2(x + 2) + 8 Distributive Property

8x - 6 = 2x + 4 + 8 Add 4 + 8

8x - 6 = 2x + 12 Add 6 to both sides

8x = 2x + 12 + 6 Add 12 + 6

8x = 2x + 18 Subtract 2x from both sides

8x - 2x = 18 Subtract 8x - 2x

6x = 18 Divide by 6

x = 3

8 0

3 years ago

{ HARDER }

cestrela7 [59]

(i):
$x = Vtcos\theta$
$Vcos\theta = \frac{x}{t}$

$y = -\frac{1}{2}gt^{2} + Vtsin\theta$
$Vsin\theta = \frac{y + \frac{1}{2}gt^{2}}{t}$

$V^{2}cos^{2}\theta + V^{2}sin^{2}\theta = \frac{x^{2}}{t^{2}} + \frac{y^{2} + gt^{2}y + \frac{1}{4}g^{2}t^{4}}{t^{2}}$
$V^{2} = \frac{x^{2}}{t^{2}} + \frac{y^{2} + gt^{2}y + \frac{1}{4}g^{2}t^{4}}{t^{2}}$
$t^{2}V^{2} = x^{2} + y^{2} + gt^{2}y + \frac{1}{4}g^{2}t^{4}$
$4t^{2}V^{2} = 4x^{2} + 4y^{2} + 4gt^{2}y + g^{2}t^{4}$
$4x^{2} + 4y^{2} + 4gt^{2}y + g^{2}t^{4} - 4t^{2}V^{2} = 0$
$4y^{2} + 4gt^{2}y + (gt^{2}t^{4} + 4x^{2} - 4t^{2}V^{2}) = 0$

(ii): Impact is when x = d.
$\text{Impact: } d = Vtcos\theta$
$t = \frac{d}{Vcos\theta}$

First impact occurs when t is minimised.
This means that Vcos theta is maximised, which means cos theta = 1, and theta = 0
$\therefore \text{First impact occurs at } \theta = 0\text{: }t = \frac{d}{V(1)} = \frac{d}{V}$

i'll do the rest later.

8 0

4 years ago

Which is the graph of the system of inequalities y 2 4x - and y = 2x + 6

SCORPION-xisa [38]

Answer:

The 1st graph

Step-by-step explanation:

Easiest and fastest way to do this is to graph both inequalities on a graphing calc.

6 0

4 years ago

Read 2 more answers

Question is attached.Step by step explanation only!​

Question is attached.Step by step explanation only!