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Stels [109]
2 years ago
15

A pianist plans to play 4 pieces at a recital from her repertoire of 20 pieces, and is carefully considering which song to play

first, second, etc. to create a good flow. How many different recital programs are possible
Mathematics
1 answer:
balu736 [363]2 years ago
4 0

There are 1,16,280 different recital programs possible.

Given: A pianist plans to play 4 pieces at a recital from her repertoire of 20 pieces and is carefully considering which song to play first, second, etc.

It means the repetition of pieces is not allowed.

When repetition is not allowed, then the number of ways to arrange n things where r things taken together is given by:-

^{n} P_{r} =\frac{n!}{(n-r)!}

Now, the number of different recital programs are:-

^{20} P_{4} =\frac{20!}{(20-4)!}=\frac{20*19*18*17*16!}{16!}=116280

Hence, there are 1,16,280 different recital programs possible.

Learn more about probability here brainly.com/question/251701

#SPJ4

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Next try to balance out your equation. You want your x's all by themselves in order to solve.

The 8x's cancel eachother out so you have -24+7= -34x.

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A group of people were asked if they had run a red light in the last year. 290 responded "yes", and 177 responded "no". Find the
GuDViN [60]

Answer:

0.621

Step-by-step explanation:

Number of people that have run a red light in the last year = 290

Number of people that have not run a red light in the last year = 177

Total number of respondents = 290 + 177

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Pr(if a person is chosen at random, they have run a red light in the last year) = \frac{number of people who has run the red light last year}{total number of respondents}

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The probability that if a person is chosen at random, they have run a red light in the last year is 0.621.

6 0
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