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natali 33 [55]
2 years ago
15

I'm having a hard time doing inequalities, and I really need help with this question. Any help will be appreciated.

Mathematics
1 answer:
Murljashka [212]2 years ago
6 0

The solution to the given compound inequality 2x - 3 < x + 2 ≤ 3x + 5 is 5 > x ≥ -3/2

<h3>Compound inequality</h3>

2x - 3 < x + 2 ≤ 3x + 5

solve differently

2x - 3 < x + 2

2x - x < 2 + 3

x < 5

x + 2 ≤ 3x + 5

x - 3x ≤ 5 - 2

-2x ≤ 3

x ≥ 3/-2

x ≥ -3/2

Therefore, the solution of the compound inequality is 5 > x ≥ -3/2

Learn more about compound inequality:

brainly.com/question/234674

#SPJ1

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3 years ago
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Please help!!!!!!!!!!!!!!!!!!
elena55 [62]

h(x)=(f\circ g)(x)\\\\h(x)=\sqrt[3]{x+3};\ f(x)=\sqrt[3]{x+2}\\\\h(x)=\sqrt[3]{x+1+2}=\sqrt[3]{(x+1)+2}=\sqrt[3]{g(x)+2}\to \boxed{g(x)=x+1}

-----------------------------------------------------------------------------------------------

f(x)=2x;\ g(x)=2x-1;\ h(x)=\sqrt{x}\\\\(f\circ g\circ h)(9)=?\\\\h(9)=\sqrt9=3\\\\(g\circ h)(9)=g(3)=2(3)-1=6-1=5\\\\(f\circ g\circ h)(9)=f(5)=2(5)=10\\------------------------------\\other\ method:\\\\(f\circ g\circ h)(x)=2(2\sqrt{x}-1)=4\sqrt{x}-2\\\\(f\circ g\circ h)(9)=4\sqrt9-2=4(3)-2=12-2=10

-------------------------------------------------------------------------------------------------

f(x)=4x+1;\ g(x)=x^2-5\\\\(f\circ g)(4)=?\\\\g(4)=4^2-5=16-5=11\\(f\circ g)(4)=f(11)=4(11)+1=44+1=45\\----------------------------------\\other\ method:\\\\(f\circ g)(x)=4(x^2-5)+1=4x^2-20+1=4x^2-19\\\\(f\circ g)(4)=4(4)^2-19=4(16)-19=64-19=45


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3 years ago
Classify the triangle by its side
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Step-by-step explanation:

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3 0
4 years ago
Plese im stuck on this question and i need this to get my grade up
Volgvan

Answer:

the answer is  x<-1

Step-by-step explanation:

-6x + 22 1/4 +2x> 9 3/4+ 16 1/2

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-4x> 4

x <-1

4 0
2 years ago
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