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olganol [36]
2 years ago
9

Find the vertex of the function given below.

Mathematics
1 answer:
zheka24 [161]2 years ago
7 0

Answer:

A

Step-by-step explanation:

given a quadratic function in standard form

y = ax² + bx + c (a ≠ 0 ) then the x- coordinate of the vertex is

x = - \frac{b}{2a}

y = 2x² + 8x + 1 ← is in standard form

with a = 2 , b = 8 , then

x = - \frac{8}{4} = - 2

substitute x = - 2 into the equation for corresponding y- coordinate

y = 2(- 2)² + 8(- 2) + 1 = 2(4) - 16 + 1 = 8 - 16 + 1 = - 7

vertex = (- 2, - 7 )

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The domain of the function is the set of all real numbers and the range of the function is the set of all values greater than -2

<h3>How to determine the domain and the range?</h3>

The function is given as:

f(x) = 2(x -4)^2 - 2

A quadratic function can take any real number as its input.

So, the domain of the function is the set of all real numbers

The vertex of the above function is:

Vertex = (4, -2)

And the leading coefficient is:

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Because the value of a is positive, then the vertex is a minimum.

This means that the range of the function is the set of all values greater than -2

Read more about domain and range at:

brainly.com/question/10197594

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8 0
2 years ago
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IgorC [24]

Answer:

a) Here we have:

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b) Here we have:

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4 years ago
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<em>Hi</em><em>!</em>

<em>Answer</em><em>:</em>

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<em>=</em><em> </em><em>6</em><em> </em><em>-</em><em> </em><em>9</em><em> </em><em>-</em><em> </em><em>b</em><em> </em><em>(</em><em>-4</em><em>)</em><em> </em><em>-</em><em> </em><em>3</em>

<em>=</em><em> </em><em>6</em><em> </em><em>-</em><em> </em><em>9</em><em> </em><em>+</em><em> </em><em>4b</em><em> </em><em>-</em><em> </em><em>3</em>

<em>=</em><em> </em><em>-6</em><em> </em><em>+</em><em> </em><em>4b</em>

<em>=</em><em> </em><em>4b</em><em> </em><em>-</em><em> </em><em>6</em>

<em>I hope I helped you! Good luck at school! </em>

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