Question

Find the vertex of the function given below.

Answer 1

Answer:

A

Step-by-step explanation:

given a quadratic function in standard form

y = ax² + bx + c (a ≠ 0 ) then the x- coordinate of the vertex is

x = - $\frac{b}{2a}$

y = 2x² + 8x + 1 ← is in standard form

with a = 2 , b = 8 , then

x = - $\frac{8}{4}$ = - 2

substitute x = - 2 into the equation for corresponding y- coordinate

y = 2(- 2)² + 8(- 2) + 1 = 2(4) - 16 + 1 = 8 - 16 + 1 = - 7

vertex = (- 2, - 7 )