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2 years ago

Find the vertex of the function given below.

Mathematics

1 answer:

zheka24 [161]2 years ago

7 0

Answer:

Step-by-step explanation:

given a quadratic function in standard form

y = ax² + bx + c (a ≠ 0 ) then the x- coordinate of the vertex is

x = - $\frac{b}{2a}$

y = 2x² + 8x + 1 ← is in standard form

with a = 2 , b = 8 , then

x = - $\frac{8}{4}$ = - 2

substitute x = - 2 into the equation for corresponding y- coordinate

y = 2(- 2)² + 8(- 2) + 1 = 2(4) - 16 + 1 = 8 - 16 + 1 = - 7

vertex = (- 2, - 7 )

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The domain of the function is the set of all real numbers and the range of the function is the set of all values greater than -2

<h3>How to determine the domain and the range?</h3>

The function is given as:

f(x) = 2(x -4)^2 - 2

A quadratic function can take any real number as its input.

So, the domain of the function is the set of all real numbers

The vertex of the above function is:

Vertex = (4, -2)

And the leading coefficient is:

a = 2

The y value of the vertex is;

y = -2

Because the value of a is positive, then the vertex is a minimum.

This means that the range of the function is the set of all values greater than -2

Read more about domain and range at:

brainly.com/question/10197594

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2 years ago

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b) Here we have:

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4 years ago

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Hi!

Answer:

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I hope I helped you! Good luck at school!

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