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Lisa [10]
3 years ago
10

6 + (-9) - (-4) - 3 help

Mathematics
1 answer:
Grace [21]3 years ago
7 0

<em>Hi</em><em>!</em>

<em>Answer</em><em>:</em>

<em>6</em><em> </em><em>+</em><em> </em><em>(</em><em>-9</em><em>)</em><em> </em><em>-</em><em> </em><em>(</em><em>-4</em><em>)</em><em> </em><em>-</em><em> </em><em>3</em><em> </em><em>=</em>

<em>=</em><em> </em><em>6</em><em> </em><em>-</em><em> </em><em>9</em><em> </em><em>-</em><em> </em><em>b</em><em> </em><em>(</em><em>-4</em><em>)</em><em> </em><em>-</em><em> </em><em>3</em>

<em>=</em><em> </em><em>6</em><em> </em><em>-</em><em> </em><em>9</em><em> </em><em>+</em><em> </em><em>4b</em><em> </em><em>-</em><em> </em><em>3</em>

<em>=</em><em> </em><em>-6</em><em> </em><em>+</em><em> </em><em>4b</em>

<em>=</em><em> </em><em>4b</em><em> </em><em>-</em><em> </em><em>6</em>

<em>I hope I helped you! Good luck at school! </em>

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Evaluate 9(x + 5y) for x = 2 and y = 5.
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Answer:

243

Step-by-step explanation:

STEP 1: Evaluate the variables

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STEP 2: Then from there you can multiply the equation

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3 years ago
Solve for the width in the formula for the area of a rectangle.
madam [21]
A = L * W
A / L = W <==

when A = 42 and W = 16.8
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4 0
3 years ago
Read 2 more answers
Let T:R²-&gt;R² be a linear transformation ,and assume that T (1,2)=(-1,1) and T(1,-1)=(2,3)
zavuch27 [327]

Answer:

(-4,-1)

Step-by-step explanation:

We are given T(1,2)=(-1,1) and T(1,-1)=(2,3) and T is a linear transformation.

This implies for scalars a and b that

T(a(1,2)+b(-1,1))=aT(1,2)+bT(-1,1)

T((a,2a)+(-b,b))=a(-1,1)+b(2,3)

T((a-b,2a+b))=(-a,a)+(2b,3b)

T((a-b,2a+b))=(-a+2b,a+3b)

This means we should be able to solve the system below to find a and b for T(3,3):

a-b=3 and 2a+b=3

Add equations to eliminate b and solve for a:

3a=6

Divide 3 on both sides:

a=2

If a-b=3 and a=2, then b=-1.

Plug in a=2, b=-1:

T((a-b,2a+b))=(-a+2b,a+3b)

T((2--1,2×2+-1)=(-2+2×-1,2+3×-1)

T(3,3)=(-4,-1).

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2 years ago
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44.49 repeated

Step-by-step explanation:

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Step-by-step explanation:

or 4 and 5

8 0
2 years ago
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