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kvv77 [185]
2 years ago
13

G.SRT.1 In the coordinate plane, quadrilateral ABCD has vertices A (1, 1), * 1 point B (5,1), C (5,9), and D (1, 9). Quadrilater

al FGHJ is shown in the coordinate plane below. What are the scale factor and the center of dilation that map quadrilateral BCD onto quadrilateral FGHJ?
Mathematics
1 answer:
Natalka [10]2 years ago
4 0

Based on the vertices of quadrilateral ABCD and Quadrilateral FGHJ, A. The scale factor is 1/2, and the center of dilation is point A.

<h3>What is the scale factor?</h3>

First, note the vertices of Quadrilateral FGHJ:

F(1,1)  G(3 ,1)  J (1 , 5)  H(3 , 5)

Find the lengths of the sides of both quadrilaterals:

FG = (3, 1) - (1, 1)                                      AB = (5,1) - (1, 1)  

= (2,0)                                                           = (4, 0)

FH = (3, 5) - (1, 1)                                      AC = (5,9) - (1, 1)  

= (2,4)                                                           = (4, 8)

AB is twice the size of FG.

AC is twice the size of FH

This shows that quadrilateral FGHJ is 1/2 the size of quadrilateral ABCD.

Find out more on dilation at brainly.com/question/10253650.

#SPJ1

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Pls help 25 points and brainliest.
puteri [66]

This is an equation that calculates potential energy and converts the value into its commercial unit.

<u>Step-by-step explanation:</u>

Step 1:

Given equation is 2 kg × 9.81 m/s² × 40 m. From the units, find the corresponding measurements. kg is the unit of mass (m), 9.81 m/s² is the acceleration due to gravity (g) and m is the unit of length or height (h).

This shows that this equation is to find potential energy. It is then converted into the commercial unit of energy (Joules).

⇒ Potential Energy = mgh = 2 kg × 9.81 m/s² × 40 m

                                            = 784.8 kg m²/s²

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3 0
3 years ago
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garik1379 [7]

Answer:

Below

Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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Step-by-step explanation:

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<h3>Answer:  32</h3>

Explanation:

If a set has n items inside it, then there will be 2^n different subsets. This includes the original set itself (since any set is a subset of itself).

Here we have n = 5 items in the given set, so there are 2^5 = 32 different subsets.

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