Answer:
0.9898 = 98.98% probability that there will not be more than one failure during a particular week.
Step-by-step explanation:
In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:
![P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}](https://tex.z-dn.net/?f=P%28X%20%3D%20x%29%20%3D%20%5Cfrac%7Be%5E%7B-%5Cmu%7D%2A%5Cmu%5E%7Bx%7D%7D%7B%28x%29%21%7D)
In which
x is the number of sucesses
e = 2.71828 is the Euler number
is the mean in the given interval.
3 failures every twenty weeks
This means that for 1 week, ![\mu = \frac{3}{20} = 0.15](https://tex.z-dn.net/?f=%5Cmu%20%3D%20%5Cfrac%7B3%7D%7B20%7D%20%3D%200.15)
Calculate the probability that there will not be more than one failure during a particular week.
Probability of at most one failure, so:
![P(X \leq 1) = P(X = 0) + P(X = 1)](https://tex.z-dn.net/?f=P%28X%20%5Cleq%201%29%20%3D%20P%28X%20%3D%200%29%20%2B%20P%28X%20%3D%201%29)
Then
![P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}](https://tex.z-dn.net/?f=P%28X%20%3D%20x%29%20%3D%20%5Cfrac%7Be%5E%7B-%5Cmu%7D%2A%5Cmu%5E%7Bx%7D%7D%7B%28x%29%21%7D)
![P(X = 0) = \frac{e^{-0.15}*0.15^{0}}{(0)!} = 0.8607](https://tex.z-dn.net/?f=P%28X%20%3D%200%29%20%3D%20%5Cfrac%7Be%5E%7B-0.15%7D%2A0.15%5E%7B0%7D%7D%7B%280%29%21%7D%20%3D%200.8607)
![P(X = 1) = \frac{e^{-0.15}*0.15^{1}}{(1)!} = 0.1291](https://tex.z-dn.net/?f=P%28X%20%3D%201%29%20%3D%20%5Cfrac%7Be%5E%7B-0.15%7D%2A0.15%5E%7B1%7D%7D%7B%281%29%21%7D%20%3D%200.1291)
Then
![P(X \leq 1) = P(X = 0) + P(X = 1) = 0.8607 + 0.1291 = 0.9898](https://tex.z-dn.net/?f=P%28X%20%5Cleq%201%29%20%3D%20P%28X%20%3D%200%29%20%2B%20P%28X%20%3D%201%29%20%3D%200.8607%20%2B%200.1291%20%3D%200.9898)
0.9898 = 98.98% probability that there will not be more than one failure during a particular week.
If 39 = (1 3/10)b, we could simplify this by writing 39 - (13/10)b.
Solve this for b by mult. both terms by (10/13):
(10*39)
----------- = (10/13)(13/10)b. Then b = 30 (answer)
13
There are 7 chairs in each row length.
Step-by-step explanation:
Let number of chairs in 1 row be 'x'.
Let total number of chairs be 'y'.
Given:
Hue can form 6 rows of a given length with 3 chairs left over.
It means that Total number of chairs is equal to chairs in 1 rows multiplied by number of rows which is 6 plus number of chairs which is left which is 3.
Framing in equation form we get.
Also Given:
Hue can form 8 rows of that same length if she gets 11 more chairs.
It means that Total number of chairs is equal to chairs in 1 rows multiplied by number of rows which is 8 minus number of chairs which is required more which is 11.
Framing in equation form we get.
From equation 1 and equation 2 we can say that L.H.S is same.
So according to law of transitivity we get;
Combining like terms we get;
Using Subtraction and Addition property we get;
Now Using Division Property we will divide both side by 2.
Hence there are 7 chairs in each row length.
The answer is d because quotient means the outcome of a division between two numbers. So therefore it has to be a division equation, which is d.