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masya89 [10]
2 years ago
14

Help

Mathematics
1 answer:
Ahat [919]2 years ago
7 0

Answer:

Step-by-step explanation:

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Thomas reads 2/9 of a book on Monday and 1/6 of it on Tuesday. He reads twice as many pages on Wednesday as on Tuesday. What fra
dezoksy [38]
1/18 is left. Thomas has 1/18 left of his book. How? What denominator can 9&6 relate to? 54? Sure, but it could be lower. How about 18? Ok. We have 18 because 9x2 and 6x3 both equal 18... 2/9 becomes 4/18 because 18 divided by 9 is 2. You multiply 2 with the two from 2/9. 1/6 becomes 3/18 because 18 divided by 6 is 3. You then multiply 3 with the one from 1/6. Put it together and TA-DA... Your answer is 1/18
8 0
3 years ago
Plot the zeros of this function:<br><br> f(x) = (x – 1)(x – 7).
vredina [299]

Answer:

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Step-by-step explanation:

The zeros of a function is where the function crosses the x-axis. The x-intercepts are the zeros of a function.

f(x) = (x - 1)(x - 7)

Let output equal to 0.

0 = (x - 1)(x - 7)

Set factors equal to 0.

x-1=0\\x=1

x-7=0\\x=7

The zeros of the function are x=1 and x=7.

5 0
3 years ago
Need help with this<br>​
AleksandrR [38]

Step-by-step explanation:

\cos( \beta  )  +  \sin( \beta )  \tan( \beta )  =  \sec( \beta )

\cos( \beta )  +  \sin( \beta )  \frac{ \sin( \beta ) }{ \cos( \beta ) }

\cos( \beta )  +  \frac{ \sin {}^{2} ( \beta ) }{ \cos( \beta ) }

\frac{ \cos {}^{2} ( \beta ) }{cos \beta }  +  \frac{ \sin {}^{2} ( \beta ) }{ \cos( \beta ) }

\frac{1}{ \cos( \beta ) }

=  \sec( \beta )

3 0
3 years ago
Read 2 more answers
You use 66 gallons of water on 2020 plants in your garden. At that rate, how much water will it take to water 3030 plants?
kykrilka [37]
99 gallons bc for each 1,010 plants their is 33 gallons so multiplying by 3 you will get 99 gallons for 3,030 plants 
6 0
3 years ago
Read 2 more answers
Simplify the expression. Write your answer as a complex number.
prohojiy [21]

Answer:

15-8i

Step-by-step explanation:

we know that

The algebraic expression is equal to

5\sqrt{9}-\sqrt{-64}}

Remember that

\sqrt{9}=3

and

i=\sqrt{-1}

so

\sqrt{-64}=i\sqrt{64}=8i

substitute

5\sqrt{9}-\sqrt{-64}}=5(3)-(8i)=15-8i

4 0
3 years ago
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