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docker41 [41]
2 years ago
9

14. Danny works part-time at Tom's Toy Store. He

Mathematics
1 answer:
jarptica [38.1K]2 years ago
5 0

Answer:

  • 21 hours in May, 63 hours in June

Step-by-step explanation:

<h3>Set up equations</h3>
  • m - May, j - June
  • m + j = 84
  • m = 1/3j
<h3>Solve by substitution, fin the value of j</h3>
  • 1/3j + j = 84
  • 4/3j = 84
  • j = 84*3/4
  • j = 63
<h3>Find m</h3>
  • m + 63 = 84
  • m = 84 - 63
  • m = 21
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3 years ago
Find f (-2) f(x)= 3x^2 - 8x + 7
Maslowich

Answer: Solving for f. Want to solve for x instead?

1 Remove parentheses.

f\times -2fx=3{x}^{2}-8x+7f×−2fx=3x

​2

​​ −8x+7

2 Use Product Rule: {x}^{a}{x}^{b}={x}^{a+b}x

​a

​​ x

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3 Regroup terms.

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​

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5 Divide both sides by xx.

{f}^{2}=-\frac{\frac{3{x}^{2}-8x+7}{2}}{x}f

​2

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​x

​

​

​2

​

​3x

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​​

​​

6 Simplify  \frac{\frac{3{x}^{2}-8x+7}{2}}{x}

​x

​

​

​2

​

​3x

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​​

​​   to  \frac{3{x}^{2}-8x+7}{2x}

​2x

​

​3x

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​​ .

{f}^{2}=-\frac{3{x}^{2}-8x+7}{2x}f

​2

​​ =−

​2x

​

​3x

​2

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​​

7 Take the square root of both sides.

f=\pm \sqrt{-\frac{3{x}^{2}-8x+7}{2x}}f=±√

​−

​2x

​

​3x

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​​

​

​​

8 Simplify  \sqrt{-\frac{3{x}^{2}-8x+7}{2x}}√

​−

​2x

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​​

​

​​   to  \sqrt{\frac{3{x}^{2}-8x+7}{2x}}\imath√

​

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​​

​

​​ ı.

f=\pm \sqrt{\frac{3{x}^{2}-8x+7}{2x}}\imathf=±√

​

​2x

​

​3x

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​​ −8x+7

​​

​

​​ ı

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f=\pm \imath \sqrt{\frac{3{x}^{2}-8x+7}{2x}}f=±ı√

​

​2x

​

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​​

​

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Done- :)

f=±ı√ ​2x 3x 2 −8x+7

​​

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Step-by-step explanation

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