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elixir [45]
2 years ago
10

PLEASE HELP

Mathematics
1 answer:
SVEN [57.7K]2 years ago
3 0

Answer:

Son's Age: 11

Mary's Age: 33

Step-by-step explanation:

Let set Mary and her son as variables,

M = Mary's age

S  = Mary's son age

<u>Breakdown:</u>

"Mary is three times as old as her son"

M = 3S

"In <em>12 years</em>, Mary's age will be one less than <u>twice her son's</u> age"

M <em>+ 12</em> = <u>2</u>(S <em>+ 12</em>) - 1

we add 12 to both sides as it will be in 12 years for both

We know that M = 3S, so we plug this in

3S + 12 = 2(S + 12) - 1

Now solve for <em>S (son's age),</em>

3S + 12 - 12 = 2(S + 12) - 1 - 12

3S = 2(S + 12) - 13

3S = 2S + 24 - 13

3S - 2S = 2S - 2S + 24 - 13

S = 24 - 13

S = 11

To find <u>Mary age</u>, plug in her son age ,

M = 3S

M = 3(11)

M = 33

Learn more about Substitution here: brainly.com/question/22340165

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