Answer:
B. (3, -2)
Step-by-step explanation:
For the table to still be a function, any added pair should not result into any x-value having different y-values. This is because, for the table to remain a function, no x-value should give different y-values. That is, each x-value must have exactly one y-value.
❌If we add the ordered pair in option A, (6, 4) to the table, y is no longer a function of x, because we would be having an x-value of 6 giving us different y-values of -13 and 4.
✅If we add the ordered pair in option B, (3, -2) to the table, y would remain a function of x, because we would be having each x-value having exactly one y-value.
❌If we add the ordered pair in option C, (0, 4) to the table, y is no longer a function of x, because we would be having an x-value of 0 giving us different y-values of -1 and 4.
❌If we add the ordered pair in option D, (-2, 5) to the table, y is no longer a function of x, because we would be having an x-value of -2 giving us different y-values of 3 and 5.
The answer is B. (3, -2).
