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babymother [125]
1 year ago
15

While conducting routine maintenance, you discover a network server that needs to

Computers and Technology
1 answer:
patriot [66]1 year ago
3 0

Answer:

tell the truth and make other people aware of what is going on inorder for them to also be hands on deck and come up with solutions to also help solve the problem

You might be interested in
What are the pros and cons of using ICT
qaws [65]

Answer:

Pros:

- Connect with friends, family in a short period of connecting time

- Faster, easier than paper

- The messages can be stored in the device for longer times, without being damaged, unlike paper files that easily get damages

- Digital communication can be done over large distances through internet and other things.

And many other pros

Cons:

- Software can be easily hacked

- Digital Communication has completelymake people become far to others. They would stop meeting face-to-face but instead of that, video call, chatting is become more popular

- Most of devices have hidden recording mechanisms that can take your information unknowingly and may be used to attack you in the future

And many other cons

Hope this helped :3

5 0
3 years ago
Write a program that prompts the user for their quarterly water bill for the last four quarters. The program should find and out
Fed [463]

Answer:

total = 0

for i in range(4):

   bill = float(input("Enter bill for quarter " + str(i+1) + ": "))

   total += bill

average = total / (4 * 3)

if average > 75:

   print("Average monthly bill is $" + str(average) + ". Too much water is being used")

if 25 <= average < 75:

   print("Average monthly bill is $" + str(average) + ". A typical amount of water is being used")

if average < 25:

   print("Average monthly bill is $" + str(average) + ". Thank you for conserving water")

Explanation:

*The code is in Python.

Create a for loop that asks the user to enter the bill for 4 quarters and calculate the total of the bills

Calculate the average monthly bill, divide the total by 12

Check the average for the given conditions. Depending on its value print the required message along with the average monthly bill

4 0
3 years ago
The Open Systems Interconnection (OSI) Reference Model: defines standards for many aspects of computing and communications withi
Advocard [28]

Answer:

is a generic description for how computers use multiple layers of protocol rules to communicate across a network.

Explanation:

OSI model stands for Open Systems Interconnection. The seven layers of OSI model architecture starts from the Hardware Layers (Layers in Hardware Systems) to Software Layers (Layers in Software Systems) and includes the following;

1. Physical Layer.

2. Data link Layer.

3. Network Layer.

4. Transport Layer.

5. Session Layer.

6. Presentation Layer.

7. Application Layer.

Hence, the Open Systems Interconnection (OSI) Reference Model is a generic description for how computers use multiple layers of protocol rules to communicate across a network.

Additionally, each layer has its unique functionality which is responsible for the proper functioning of the communication services.

8 0
3 years ago
Write an application that determines whether the first two files are located in the same folder as the third one. The program sh
marissa [1.9K]

Answer:

The program in Python is as follows:

fname1 = input("Filepath 1: ").lower()

fname2 = input("Filepath 2: ").lower()

fname3 = input("Filepath 3: ").lower()

f1dir = ""; f2dir = ""; f3dir = ""

fnamesplit = fname1.split("/")

for i in range(len(fnamesplit)-1):

   f1dir+=fnamesplit[i]+"/"

fnamesplit = fname2.split("/")

for i in range(len(fnamesplit)-1):

   f2dir+=fnamesplit[i]+"/"

fnamesplit = fname3.split("/")

for i in range(len(fnamesplit)-1):

   f3dir+=fnamesplit[i]+"/"

if f1dir == f2dir == f3dir:

   print("Files are in the same folder")

else:

   print("Files are in the different folder")

Explanation:

The next three lines get the file path of the three files

<em>fname1 = input("Filepath 1: ").lower()</em>

<em>fname2 = input("Filepath 2: ").lower()</em>

<em>fname3 = input("Filepath 3: ").lower()</em>

This initializes the directory of the three files to an empty string

f1dir = ""; f2dir = ""; f3dir = ""

This splits file name 1 by "/"

fnamesplit = fname1.split("/")

This iteration gets the directory of file 1 (leaving out the file name)

<em>for i in range(len(fnamesplit)-1):</em>

<em>    f1dir+=fnamesplit[i]+"/"</em>

This splits file name 2 by "/"

fnamesplit = fname2.split("/")

This iteration gets the directory of file 2 (leaving out the file name)

<em>for i in range(len(fnamesplit)-1):</em>

<em>    f2dir+=fnamesplit[i]+"/"</em>

This splits file name 3 by "/"

fnamesplit = fname3.split("/")

This iteration gets the directory of file 3 (leaving out the file name)

<em>for i in range(len(fnamesplit)-1):</em>

<em>    f3dir+=fnamesplit[i]+"/"</em>

This checks if the file directories hold the same value

This is executed, if yes

<em>if f1dir == f2dir == f3dir:</em>

<em>    print("Files are in the same folder")</em>

This is executed, if otherwise

<em>else:</em>

<em>    print("Files are in the different folder")</em>

5 0
3 years ago
The seven basic parts of a computer are
True [87]
Monitor, keyboard, CPU, mouse, and I believe the USB drive , DVD drive and hardware system
4 0
3 years ago
Read 2 more answers
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