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Iteru [2.4K]
1 year ago
5

(x + 2)*(x^2 -2*x+4) - (x^3 -12)

Mathematics
1 answer:
Ivahew [28]1 year ago
3 0

Answer:

  • \large{ \boxed{ \tt{20}}}

- Please see the attached picture for full solution!:)

------------ HappY LearninG <3 -----------

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What is the value of m in the equation 5m − 7 = 6m 11? 18 1 −18 −1.
denpristay [2]

Answer:

-7 = m

Step-by-step explanation:

5m − 7 = 6m

Subtract 5m from each side

5m-5m − 7 = 6m-5m

-7 = m

6 0
1 year ago
= 8 cm, height = 67 cm.
zavuch27 [327]

Answer:

45

Step-by-step explanation:

8cm=67-8

5 0
3 years ago
15
Butoxors [25]

Step-by-step explanation:

1/2 represents every fraction, where the denominator (bottom part) is twice the numerator (top part).

like 4/8 or 6/12 or 128/256 or ...

what do we need in the denominator to calculate with 15/16 ?

the same : 16.

and what is half of 16 ? 8.

so, we need the 1/2 based on 16th = 8/16.

so, the dog ate 8/16 (1/2) of the original 15/16.

what was left was

15/16 - 8/16 = 7/16 pound

7 0
2 years ago
Is it true that the planes x + 2y − 2z = 7 and x + 2y − 2z = −5 are two units away from the plane x + 2y − 2z = 1?
zhuklara [117]

Lets Find It Out..

First we'll find the equation of ALL planes parallel to the original one.

As a model consider this lesson:

Equation of a plane parallel to other

The normal vector is:
<span><span>→n</span>=<1,2−2></span>

The equation of the plane parallel to the original one passing through <span>P<span>(<span>x0</span>,<span>y0</span>,<span>z0</span>)</span></span>is:

<span><span>→n</span>⋅< x−<span>x0</span>,y−<span>y0</span>,z−<span>z0</span>>=0</span>
<span><1,2,−2>⋅<x−<span>x0</span>,y−<span>y0</span>,z−<span>z0</span>>=0</span>
<span>x−<span>x0</span>+2y−2<span>y0</span>−2z+2<span>z0</span>=0</span>
<span>x+2y−2z−<span>x0</span>−2<span>y0</span>+2<span>z0</span>=0</span>

Or

<span>x+2y−2z+d=0</span> [1]
where <span>a=1</span>, <span>b=2</span>, <span>c=−2</span> and <span>d=−<span>x0</span>−2<span>y0</span>+2<span>z0</span></span>

Now we'll find planes that obey the previous formula and at a distance of 2 units from a point in the original plane. (We should expect 2 results, one for each half-space delimited by the original plane.)
As a model consider this lesson:

Distance between 2 parallel planes

In the original plane let's choose a point.
For instance, when <span>x=0</span> and <span>y=0</span>:
<span>x+2y−2z=1</span> => <span>0+2⋅0−2z=1</span> => <span>z=−<span>12</span></span>
<span>→<span>P1</span><span>(0,0,−<span>12</span>)</span></span>

In the formula of the distance between a point and a plane (not any plane but a plane parallel to the original one, equation [1] ), keeping <span>D=2</span>, and d as d itself, we get:

<span><span>D=<span><span>|a<span>x1</span>+b<span>y1</span>+c<span>z1</span>+d|</span><span>√<span><span>a2</span>+<span>b2</span>+<span>c2</span></span></span></span></span>
<span>2=<span><span><span>∣∣</span>1⋅0+2⋅0+<span>(−2)</span>⋅<span>(−<span>12</span>)</span>+d<span>∣∣</span></span><span>√<span>1+4+4</span></span></span></span>
<span><span>|d+1|</span>=2⋅3</span> => <span><span>|d+1|</span>=6</span>First solution:
<span>d+1=6</span> => <span>d=5</span>
<span>→x+2y−2z+5=0</span>Second solution:
<span>d+1=−6</span> => <span>d=−7</span>
<span>→x+2y−2z−7=<span>0</span></span></span>
8 0
2 years ago
Which of the following pairs of functions are inverses of each other?
Serggg [28]

Answer:

<em>The answer is (B).</em>

Step-by-step explanation:

A). y = f(x) = 6(x - 2) + 3 ⇔ y = 6x - 12 + 3 ⇔ 6x = y + 9 ⇔ x = \frac{y+9}{6}

g(x) = \frac{x+9}{6} is inverse function of f(x) and ≠ \frac{x+2}{6} - 3

<em>B).</em> y = f(x) = \frac{5x}{4} - 3 ⇔ 4y = 5x - 12 ⇔ x = \frac{4y+12}{5}  

g(x) = \frac{4(x + 3)}{5} is inverse of f(x)

6 0
3 years ago
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