1 year ago

(x + 2)(x^2 -2x+4) - (x^3 -12)

Mathematics

1 answer:

Ivahew [28]1 year ago

3 0

Answer:

$\large{ \boxed{ \tt{20}}}$

- Please see the attached picture for full solution!:)

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Answer:

Therefore, equation of the line that passes through (16,-7) and is perpendicular to the line $2x-3y=12$ is $3x+2y=34$

Step-by-step explanation:

Given:

$2x-3y=12$

To Find:

Equation of line passing through ( 16, -7) and is perpendicular to the line

$2x-3y=12$

Solution:

$2x-3y=12$ ...........Given

$\therefore y=\dfrac{2}{3}\times x-4$

Comparing with,

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Where m =slope

We get

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Substituting m1 we get m2 as

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Therefore the slope of the required line passing through (16 , -7) will have the slope,

$m2=-\dfrac{3}{2}$

Now the equation of line in slope point form given by

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Substituting the point (16 , -7) and slope m2 we will get the required equation of the line,

$(y-7)=-\dfrac{3}{2}\times (x-16)\\\\2y+14=-3x+48\\3x+2y=34......Equation\ of\ line$

Therefore, equation of the line that passes through (16,-7) and is perpendicular to the line $2x-3y=12$ is $3x+2y=34$

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Read 2 more answers

(x + 2)*(x^2 -2*x+4) - (x^3 -12)

(x + 2)(x^2 -2x+4) - (x^3 -12)