All categories

2 years ago

(x + 2)(x^2 -2x+4) - (x^3 -12)

Mathematics

1 answer:

Ivahew [28]2 years ago

3 0

Answer:

$\large{ \boxed{ \tt{20}}}$

- Please see the attached picture for full solution!:)

------------ HappY LearninG <3 -----------

You might be interested in

Pls help pls pls pls

VLD [36.1K]

Answer:

Step-by-step explanation:

7 0

2 years ago

The diagram shows a track composed with a semicircle on each end. The area of the rectangle is 8,400 square meters. What is the

MrRa [10]

Answer:

468.4 meters

Step-by-step explanation:

Find the width of the rectangle.

The area of a rectangle is A=length*width. Substitute the values of length and area and solve for width.

A=length*width

8,400=140*width

60= width

Use the width of the rectangle to find the circumference of the semicircles. Since each semicircle is half of a circle, the perimeter of the two semicircles is equal to the circumference of one circle.

The circumference of a circle is equal to pid, where d is the diameter. The diameter of the semicircle is the same as the width of the rectangle.

So, the diameter is 60 meters. Substitute the diameter into the formula for the circumference and simplify using 3.14 for pi.

≈188.4

(2 times 140)+ 188.4

So, the perimeter of the track is 468.4 meters.

7 0

3 years ago

Am I correct? If not please explain why!

Kipish [7]

yes, you are correct. every input corresponds to only one output

6 0

3 years ago

An ant weighs 2 x 10^-3 grams, and a lion weighs 1 x 10^5. The lion's weight is 5 x 10^x times greater than the ant's weight. Wh

julsineya [31]

Answer:

x=7

Step-by-step explanation:

Information provided

Weight of ant= $2*10^{-3} grams$

Weight of lion= $1*10^{5}$ but units are not provided, assuming this unit is also grams

How many times lion's weight exceed an ant

$\frac {1*10^{5}}{2*10^{-3}}=50000000$

= $5*10^{7}$

Therefore, the value of x=7 if the unit for weight of lion is assumed to be same as unit for weight of an ant

4 0

3 years ago

How do I solve

Maslowich

$Use:\\\\(ab)^n=a^nb^n\\\\(a^n)^m=a^{nm}\\\\a^n\cdot a^m=a^{n+m}\\\\\sqrt[n]{a}=a^\frac{1}{n}\\------------------------\\\\\left(16n^4\right)^{\frac{5}{4}}=16^\frac{5}{4}\left(n^4\right)^\frac{5}{4}=16^{1\frac{1}{4}}n^{4\cdot\frac{5}{4}}=16^{1+\frac{1}{4}}n^5=16^1\cdot16^\frac{1}{4}\cdot n^5\\\\=16\cdot\sqrt[4]{16}\cdot n^5=16\cdot2\cdot n^5=\boxed{32n^5}\\\\\sqrt[4]{16}=2\ because\ 2^4=16\\\\\text{Answer}\ \boxed{\left(16n^4\right)^\frac{5}{4}=32n^5}$

4 0

3 years ago

(x + 2)*(x^2 -2*x+4) - (x^3 -12)

(x + 2)(x^2 -2x+4) - (x^3 -12)