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3 years ago

I have problems with this

Mathematics

2 answers:

d1i1m1o1n [39]3 years ago

7 0

Answer:

33°

Step-by-step explanation:

Exterior angle = sum of interior angles

145 = 112 + x

x = 145 - 112

x = 33°

aleksandr82 [10.1K]3 years ago

4 0

Answer:

x =33

Step-by-step explanation:

The exterior angle on a triangle is equal to sum of the opposite interior angles

145 = x+112

Subtract 112 from each side

145-112 = x+112-112

33 =x

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Perimeter=2(w+l)
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41.1=6w
w=6.85

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3 years ago

5000 sheets of paper cost $115 how much does a singcost

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3 years ago

what is the height of a rectangular prism that has a volume of 280 cubic meters , a length of 8 meters, and width of 7 meters?

murzikaleks [220]

Volume = L x W x H

V = 280

L = 8 m

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3 years ago

R Problem Old Faithful is a geyser located in Yellowstone Nation Park in Wyoming. It received the name "Old Faithful" by the Was

Tpy6a [65]

Answer:

Step-by-step explanation:

The first 6 rows of the eruptions data :

eruptions waiting

1 3.600 79

2 1.800 54

3 3.333 74

4 2.283 62

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6 2.883 55

R code :

1. You can directly access the "Faithful" data in R without importing the data. The dataset faithful is present in the R or you can load the datasets. or use install the datasets.load. package

If you have the data in a text file, make sure all the columns and rows are separated by commas

Step 1: open notepad

Step 2: enter data with no spaces but only commas

Step 3: save the file as ‘faithful.txt’ on your Desktop

# Get R help

?read.table

# Import the data

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sep = ",")

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8 0

3 years ago

Use the mid-point rule with n = 4 to approximate the area of the region bounded by y = x3 and y = x. (10 points)

USPshnik [31]

See the graph attached.

The midpoint rule states that you can calculate the area under a curve by using the formula:
$M_{n} = \frac{b - a}{2} [ f(\frac{x_{0} + x_{1} }{2}) + f(\frac{x_{1} + x_{2} }{2}) + ... + f(\frac{x_{n-1} + x_{n} }{2})]$

In your case:
a = 0
b = 1
n = 4
x₀ = 0
x₁ = 1/4
x₂ = 1/2
x₃ = 3/4
x₄ = 1

Therefore, you'll have:
$M_{4} = \frac{1 - 0}{4} [ f(\frac{0 + \frac{1}{4} }{2}) + f(\frac{ \frac{1}{4} + \frac{1}{2} }{2}) + f(\frac{\frac{1}{2} + \frac{3}{4} }{2}) + f(\frac{\frac{3}{4} + 1} {2})]$
$M_{4} = \frac{1}{4} [ f(\frac{1}{8}) + f(\frac{3}{8}) + f(\frac{5}{8}) + f(\frac{7}{8})]$

Now, to evaluate your f(x), you need to look at the graph and notice that:
f(x) = x - x³

Therefore:
$M_{4} = \frac{1}{4} [(\frac{1}{8} - (\frac{1}{8})^{3}) + (\frac{3}{8} - (\frac{3}{8})^{3}) + (\frac{5}{8} - (\frac{5}{8})^{3}) + (\frac{7}{8} - (\frac{7}{8})^{3})]$

$M_{4} = \frac{1}{4} [(\frac{1}{8} - \frac{1}{512}) + (\frac{3}{8} - \frac{27}{512}) + (\frac{5}{8} - \frac{125}{512}) + (\frac{7}{8} - \frac{343}{512})]$

M₄ = 1/4 · (2 - 478/512)
= 0.2666

Hence, the <span>area of the region bounded by y = x³ and y = x</span> is approximately 0.267 square units.

6 0

4 years ago